Compute the heat flux integral Φ Þ= √¶·¹ q.nds, where S is the surface of a cylinder of length L = 1 and radius R = 1, centered at (x, y) = (1,1). The heat flux satisfies Fourier's law q=-kVT, where k = 10 is the thermal conductivity and T = 2 2 + xy. Q -X

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Compute the heat flux integral
› = √¶·
Φ
q.nds,
where S is the surface of a cylinder of length L = 1 and radius
R = 1, centered at (x, y) = (1, 1). The heat flux satisfies Fourier's law
q=-kVT,
where k = 10 is the thermal conductivity and
x²
2
T
y²
2
+ xy.
O
1-
-X
Transcribed Image Text:Compute the heat flux integral › = √¶· Φ q.nds, where S is the surface of a cylinder of length L = 1 and radius R = 1, centered at (x, y) = (1, 1). The heat flux satisfies Fourier's law q=-kVT, where k = 10 is the thermal conductivity and x² 2 T y² 2 + xy. O 1- -X
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