Compute the first-order partial derivatives of the function V = 15tr² (Use symbolic notation and fractions where needed.) av ər = 30лrh

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.CR: Chapter 9 Review
Problem 13CR
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### Understanding First-Order Partial Derivatives

#### Problem Statement
Compute the first-order partial derivatives of the function \( V = 15\pi r^2 h \).

(Use symbolic notation and fractions where needed.)

#### Solution
To find the first-order partial derivatives of the given function with respect to \( r \) and \( h \), we differentiate the function \( V \) with respect to each variable separately, treating the other variable as a constant.

1. **Partial Derivative with respect to \( r \):**
\[
\frac{\partial V}{\partial r} = 30\pi rh
\]

2. **Partial Derivative with respect to \( h \):**
\[
\frac{\partial V}{\partial h} = 15\pi r^2
\]

##### Partial Derivative Explanation
- **\(\frac{\partial V}{\partial r}\)**: This represents how the volume \( V \) changes as the radius \( r \) changes, while keeping the height \( h \) constant.
- **\(\frac{\partial V}{\partial h}\)**: This represents how the volume \( V \) changes as the height \( h \) changes, while keeping the radius \( r \) constant.

In this problem, the calculated partial derivative with respect to \( h \) (i.e., \(\frac{\partial V}{\partial h}\)) is:
\[
\frac{\partial V}{\partial h} = 15 r^2
\]
but was incorrectly evaluated as \( \frac{\partial V}{\partial h} = 15hr^2 \). The correct form has been boxed.

### Conclusion
Understanding partial derivatives is crucial, especially in multivariable calculus, as it helps in understanding how a function changes with respect to one variable while keeping the other(s) constant.
Transcribed Image Text:### Understanding First-Order Partial Derivatives #### Problem Statement Compute the first-order partial derivatives of the function \( V = 15\pi r^2 h \). (Use symbolic notation and fractions where needed.) #### Solution To find the first-order partial derivatives of the given function with respect to \( r \) and \( h \), we differentiate the function \( V \) with respect to each variable separately, treating the other variable as a constant. 1. **Partial Derivative with respect to \( r \):** \[ \frac{\partial V}{\partial r} = 30\pi rh \] 2. **Partial Derivative with respect to \( h \):** \[ \frac{\partial V}{\partial h} = 15\pi r^2 \] ##### Partial Derivative Explanation - **\(\frac{\partial V}{\partial r}\)**: This represents how the volume \( V \) changes as the radius \( r \) changes, while keeping the height \( h \) constant. - **\(\frac{\partial V}{\partial h}\)**: This represents how the volume \( V \) changes as the height \( h \) changes, while keeping the radius \( r \) constant. In this problem, the calculated partial derivative with respect to \( h \) (i.e., \(\frac{\partial V}{\partial h}\)) is: \[ \frac{\partial V}{\partial h} = 15 r^2 \] but was incorrectly evaluated as \( \frac{\partial V}{\partial h} = 15hr^2 \). The correct form has been boxed. ### Conclusion Understanding partial derivatives is crucial, especially in multivariable calculus, as it helps in understanding how a function changes with respect to one variable while keeping the other(s) constant.
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