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Compute the EQUIVALENT RESISTANCE of the circuit shown below. Then find the voltage drop across each resistor, the current through each resistor, & the current put out by the battery (lo). (R₁ = 5S2, R₂ = 10 S2, R₂ = 792, R4 = 42, and Vo=22 V.) R₂ Vo R₁ www R3 R4 Reg5.88461 Io = I₁ = 1₂ = 13 = 14 = x 22 V₁ = V₂ = V3 = V4=

Compute the EQUIVALENT RESISTANCE of the circuit shown below. Then find the voltage drop across each resistor, the current through each resistor, & the current put out by the battery (lo). (R₁ = 5S2, R₂ = 10 S2, R₂ = 792, R4 = 42, and Vo=22 V.) R₂ Vo R₁ www R3 R4 Reg5.88461 Io = I₁ = 1₂ = 13 = 14 = x 22 V₁ = V₂ = V3 = V4=

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Compute the EQUIVALENT RESISTANCE of the circuit shown below. Then find the voltage drop across each resistor, the current through each resistor, & the current put out by the battery (lo). (R₁ = 5 2, R₂ = 102, R₂ = 72, R4 = 42, and V₁ = 22 V.) R₂ Vo R₁ W R3 R4 Reg = 5.88461 Io I₁ = I₂ = I3 = I4 = ΧΩ V₁ = V₂ = V3 = V4 =
Transcribed Image Text:Compute the EQUIVALENT RESISTANCE of the circuit shown below. Then find the voltage drop across each resistor, the current through each resistor, & the current put out by the battery (lo). (R₁ = 5 2, R₂ = 102, R₂ = 72, R4 = 42, and V₁ = 22 V.) R₂ Vo R₁ W R3 R4 Reg = 5.88461 Io I₁ = I₂ = I3 = I4 = ΧΩ V₁ = V₂ = V3 = V4 =
Expert Solution
Step 1

The resistors in the lower branch are in series.

RS=R2+R3+R4RS=10 Ω+7 Ω+4 ΩRS=21 Ω

The resistor RS is in series with R1. So, the equivalent resistance will be:

Req=R1RSR1+RSReq=(5 Ω)(21 Ω)5 Ω+21 ΩReq=4.038 Ω

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