Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 2 - 4 4 3 1 2 1 5 - 2 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) OA. Using this expansion, the determinant is (-4)( − 8) − (1)( − 8) + (5)( − 8) = B. Using this expansion, the determinant is −(− 4)( − 8) + (1)( − 8) − (5)( − 8) = C. Using this expansion, the determinant is (2)(- 12) − ( − 4)( − 8) + (4)(14) = - D. Using this expansion, the determinant is − (2)( − 12) + (− 4)( − 8) - (4)(14) =
Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column. 2 - 4 4 3 1 2 1 5 - 2 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) OA. Using this expansion, the determinant is (-4)( − 8) − (1)( − 8) + (5)( − 8) = B. Using this expansion, the determinant is −(− 4)( − 8) + (1)( − 8) − (5)( − 8) = C. Using this expansion, the determinant is (2)(- 12) − ( − 4)( − 8) + (4)(14) = - D. Using this expansion, the determinant is − (2)( − 12) + (− 4)( − 8) - (4)(14) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column.
\[
\begin{vmatrix}
2 & -4 & 4 \\
3 & 1 & 2 \\
1 & 5 & -2 \\
\end{vmatrix}
\]
---
Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answer.)
- **A.** Using this expansion, the determinant is \((-4)(-8) - (1)(-8) + (5)(-8) = \; \_\_\_\_\).
- **B.** Using this expansion, the determinant is \(-(-4)(-8) + (1)(-8) - (5)(-8) = \; \_\_\_\_\).
- **C.** Using this expansion, the determinant is \(2(-12) - (-4)(-8) + (4)(14) = \; \_\_\_\_\).
- **D.** Using this expansion, the determinant is \((-2)(-12) + (-4)(-8) - (4)(14) = \; \_\_\_\_\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe00cebfb-aec4-474d-8979-79a2d105b819%2F00a264e9-5dc5-4566-a85a-980b2591b0ef%2F95adkir_processed.png&w=3840&q=75)
Transcribed Image Text:Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion down the second column.
\[
\begin{vmatrix}
2 & -4 & 4 \\
3 & 1 & 2 \\
1 & 5 & -2 \\
\end{vmatrix}
\]
---
Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answer.)
- **A.** Using this expansion, the determinant is \((-4)(-8) - (1)(-8) + (5)(-8) = \; \_\_\_\_\).
- **B.** Using this expansion, the determinant is \(-(-4)(-8) + (1)(-8) - (5)(-8) = \; \_\_\_\_\).
- **C.** Using this expansion, the determinant is \(2(-12) - (-4)(-8) + (4)(14) = \; \_\_\_\_\).
- **D.** Using this expansion, the determinant is \((-2)(-12) + (-4)(-8) - (4)(14) = \; \_\_\_\_\).
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