Compute the determinant of the following matrix using a cofactor expansion across the first row. 3 7 - 6 A= 2 0 4 6 3 Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) O A. Using this expansion, the determinant is (3)(- 30) - (7)(- 14) + (- 6)(12) = O B. Using this expansion, the determinant is (3)(- 30) - (2)(- 14) + (4)(12) = c. Using this expansion, the determinant is (3)(- 30) + (2)(- 14) + (4)(12) = O D. Using this expansion, the determinant is (3)(- 30) + (7)(- 14) + (- 6)(12) = LO

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Compute the Determinant of the Following Matrix Using a Cofactor Expansion Across the First Row

Given Matrix:
\[ A = \begin{bmatrix} 3 & 7 & -6 \\ 2 & 0 & 5 \\ 4 & 6 & 3 \end{bmatrix} \]

Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice.

**(Simplify your answer.)**

A. Using this expansion, the determinant is:
\[ 3(-30) - 7(-14) + (-6)(12) = \]
⬜

B. Using this expansion, the determinant is:
\[ 3(-30) - 7(-14) + 4(12) = \]
⬜

C. Using this expansion, the determinant is:
\[ 3(-30) + 2(-14) + 4(12) = \]
⬜

D. Using this expansion, the determinant is:
\[ 3(-30) + 7(-14) + (-6)(12) = \]
⬜
Transcribed Image Text:### Compute the Determinant of the Following Matrix Using a Cofactor Expansion Across the First Row Given Matrix: \[ A = \begin{bmatrix} 3 & 7 & -6 \\ 2 & 0 & 5 \\ 4 & 6 & 3 \end{bmatrix} \] Compute the determinant using a cofactor expansion across the first row. Select the correct choice below and fill in the answer box to complete your choice. **(Simplify your answer.)** A. Using this expansion, the determinant is: \[ 3(-30) - 7(-14) + (-6)(12) = \] ⬜ B. Using this expansion, the determinant is: \[ 3(-30) - 7(-14) + 4(12) = \] ⬜ C. Using this expansion, the determinant is: \[ 3(-30) + 2(-14) + 4(12) = \] ⬜ D. Using this expansion, the determinant is: \[ 3(-30) + 7(-14) + (-6)(12) = \] ⬜
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