Computé th di 1038. A car starts from rest and reaches a speed of 48 ft per sec in 15 sec. The acceleration increases from zero uniformly with time for the first 6 sec after which it 294 ft Ans. 8 = remains constant. Compute the distance traveled in 15 sec. 00 the sccelera-

Structural Analysis
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Chapter2: Loads On Structures
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A car starts from rest and raches a peed of 48ft
FIG.
FIG. P-1033.
1038. A particle having an initial velocity of 200 ft per sec decelerates accordine
tɔ the a-t curve in Fig. P-1036. Compute the change in displacement in the tim
interval of 30 sec.
|v (ft/sec)
| (f/sec*)
30
20
30
t (sec)
18
t (sec)
12
18
-30
FIG. P-1035.
FIG. P-1036.
1037. A car moving at 60 ft per sec is brought to rest in 12 sec with a decelera-
tion which varies uniformly with time from 2 ft per sec² to a maximum deceleration.
Compute the distance traveled in stopping.
Ans.
432 ft
1038. A car starts from rest and reaches a speed of 48 ft per sec in 15 sec. The
acceleration increases from zero uniformly with time for the first 6 sec after which it
remains constant. Compute the distance traveled in 15 sec.
Ans. 8 = 294 ft
1039. A car accelerates for t sec from rest to a velocity of 48 ft per sec, the accelera-
tion increasing uniformly from zero to 12 ft per sec?. During the next 4 sec, the
car decelerates at a constant rate to a velocity of 4 ft per sec. Sketch the a-t, v-t,
and 8-t curves.
1040. An object attains a velocity of 16 ft per sec by moving in a straight line
with an acceleration which varies uniformly from zero to 8 ft per sec² in 6 sec. Com-
pute its initial velocity and the change
Solve by using motion curves and check by calculus.
displacement during the 6-sec interval.
Ans. v. =-8 ft per sec; As = 0
1041. The acceleration of an object decreases uniformly from 8 ft per sec² to
zero in 6 sec at which time its velocity is 10 ft per sec. Find the initial velocity and
Transcribed Image Text:FIG. FIG. P-1033. 1038. A particle having an initial velocity of 200 ft per sec decelerates accordine tɔ the a-t curve in Fig. P-1036. Compute the change in displacement in the tim interval of 30 sec. |v (ft/sec) | (f/sec*) 30 20 30 t (sec) 18 t (sec) 12 18 -30 FIG. P-1035. FIG. P-1036. 1037. A car moving at 60 ft per sec is brought to rest in 12 sec with a decelera- tion which varies uniformly with time from 2 ft per sec² to a maximum deceleration. Compute the distance traveled in stopping. Ans. 432 ft 1038. A car starts from rest and reaches a speed of 48 ft per sec in 15 sec. The acceleration increases from zero uniformly with time for the first 6 sec after which it remains constant. Compute the distance traveled in 15 sec. Ans. 8 = 294 ft 1039. A car accelerates for t sec from rest to a velocity of 48 ft per sec, the accelera- tion increasing uniformly from zero to 12 ft per sec?. During the next 4 sec, the car decelerates at a constant rate to a velocity of 4 ft per sec. Sketch the a-t, v-t, and 8-t curves. 1040. An object attains a velocity of 16 ft per sec by moving in a straight line with an acceleration which varies uniformly from zero to 8 ft per sec² in 6 sec. Com- pute its initial velocity and the change Solve by using motion curves and check by calculus. displacement during the 6-sec interval. Ans. v. =-8 ft per sec; As = 0 1041. The acceleration of an object decreases uniformly from 8 ft per sec² to zero in 6 sec at which time its velocity is 10 ft per sec. Find the initial velocity and
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