Compute each of the following line integrals. (a) a ds, where C is the portion of the parabola from (0,0) to (1, 1), followed by the line segment from (1, 1) to (–1, 4).

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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7_a. This question was asked before and the answer was given. (Please see the attached which has partial answer). In the given answer C_1 is considered as a line but the question says it is part of the parabola opening up. So my question is shouldn't C-1 should be y=X^2 since it is part of the parabola?

Please take a look at it and give some good explanation so that I can understand this problem. Thank you.

Compute each of the following line integrals.
(a)
x ds, where C is the portion of the parabola from (0,0) to (1, 1), followed by the
line segment from (1, 1) to (-1, 4).
The parabola opens upward.
Transcribed Image Text:Compute each of the following line integrals. (a) x ds, where C is the portion of the parabola from (0,0) to (1, 1), followed by the line segment from (1, 1) to (-1, 4). The parabola opens upward.
Step 1
We have to find the value of oxds where Cis the portion of the parabola from (0, 0) to
(1, 1),followed by the line segment from (1, 1) to (-1,4)
This can be solved by the formula,
Ses (x, y. z)ds = [" f (x (1), y (1), z (1) /(x (1)² + (v (1)° + (2 (1)* )dt
→ ScS (x, y)ds = L, f (x (1), y (1) /œ (1)° + v° (1)°²dt
Sef (x, y, z)ds = [c, f (x, y, z)ds + fc,f (x, y, z)ds + ... + Sc,ƒ (x, y, z)ds
%3D
where C = C U C2 U ... Cn
Step 2
Now C'is as given in the figure:
(-1,4
C2
(1,1)
C1
(0,0)
Transcribed Image Text:Step 1 We have to find the value of oxds where Cis the portion of the parabola from (0, 0) to (1, 1),followed by the line segment from (1, 1) to (-1,4) This can be solved by the formula, Ses (x, y. z)ds = [" f (x (1), y (1), z (1) /(x (1)² + (v (1)° + (2 (1)* )dt → ScS (x, y)ds = L, f (x (1), y (1) /œ (1)° + v° (1)°²dt Sef (x, y, z)ds = [c, f (x, y, z)ds + fc,f (x, y, z)ds + ... + Sc,ƒ (x, y, z)ds %3D where C = C U C2 U ... Cn Step 2 Now C'is as given in the figure: (-1,4 C2 (1,1) C1 (0,0)
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