Compton used photons of wavelength 4

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**Compton Scattering Problem**

Compton used photons of wavelength 0.0711 nm.

(a) What is the energy of these incident photons?

(b) What is the wavelength of the photons scattered at an angle of 180°?

(c) What is the energy of the photons scattered at an angle of 180°?

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**Explanation for Educational Context:**

This problem explores Compton scattering, which is an interaction between photons and matter where the photons are scattered and their wavelengths change. The questions focus on calculating the energies and wavelengths involved in this phenomenon, particularly considering a scattering angle of 180°. 

To solve this:

- **For (a):** Use the relationship between energy and wavelength, \( E = \frac{hc}{\lambda} \), where \( h \) is Planck's constant and \( c \) is the speed of light.

- **For (b):** Apply the Compton wavelength shift formula, \( \lambda' - \lambda = \frac{h}{mc}(1 - \cos \theta) \), where \( \lambda' \) is the wavelength after scattering, \( m \) is the electron mass, and \( \theta \) is the scattering angle.

- **For (c):** Use the energy-wavelength relationship again for the scattered photons.
Transcribed Image Text:**Compton Scattering Problem** Compton used photons of wavelength 0.0711 nm. (a) What is the energy of these incident photons? (b) What is the wavelength of the photons scattered at an angle of 180°? (c) What is the energy of the photons scattered at an angle of 180°? --- **Explanation for Educational Context:** This problem explores Compton scattering, which is an interaction between photons and matter where the photons are scattered and their wavelengths change. The questions focus on calculating the energies and wavelengths involved in this phenomenon, particularly considering a scattering angle of 180°. To solve this: - **For (a):** Use the relationship between energy and wavelength, \( E = \frac{hc}{\lambda} \), where \( h \) is Planck's constant and \( c \) is the speed of light. - **For (b):** Apply the Compton wavelength shift formula, \( \lambda' - \lambda = \frac{h}{mc}(1 - \cos \theta) \), where \( \lambda' \) is the wavelength after scattering, \( m \) is the electron mass, and \( \theta \) is the scattering angle. - **For (c):** Use the energy-wavelength relationship again for the scattered photons.
Expert Solution
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Given:

Wavelength of Photons=0.0711nm

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