Compound axial member ABC has a uniform diameter ofd = 1.50 in. Segment (1) is an aluminum [E1 = 10000 ksi] alloy. The length of segment (1) is L1 = 80 in. • Segment (2) is a copper [E2 = 17000 ksi] alloy. The length of segment (2) is L2= 112 in. When axial force Pis applied, a strain gage attached to copper segment (2) measures a normal strain of ɛ = 1700 pin./in. i longitudinal direction. What is the total elongation of member ABC? L2 (1) A Aluminum (2) Соpрer
Compound axial member ABC has a uniform diameter ofd = 1.50 in. Segment (1) is an aluminum [E1 = 10000 ksi] alloy. The length of segment (1) is L1 = 80 in. • Segment (2) is a copper [E2 = 17000 ksi] alloy. The length of segment (2) is L2= 112 in. When axial force Pis applied, a strain gage attached to copper segment (2) measures a normal strain of ɛ = 1700 pin./in. i longitudinal direction. What is the total elongation of member ABC? L2 (1) A Aluminum (2) Соpрer
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Compound axial member ABC has a uniform diameter of d = 1.50 in.
Segment (1) is an aluminum [E1 = 10000 ksi] alloy. The length of segment (1) is L1 = 80 in.
• Segment (2) is a copper [E2 = 17000 ksi] alloy. The length of segment (2) is L2 = 112 in.
When axial force P is applied, a strain gage attached to copper segment (2) measures a normal strain of ɛ2 = 1700 pin./in. in
longitudinal direction.
What is the total elongation of member ABC?
L2
(1)
d
Aluminum
В
(2)
Сopper](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d8742a9-708f-4b11-8588-6f7298fbb953%2F8e4f4b3b-e0c2-477a-ac0e-2436660ee9dd%2F2pomfp4_processed.png&w=3840&q=75)
Transcribed Image Text:Compound axial member ABC has a uniform diameter of d = 1.50 in.
Segment (1) is an aluminum [E1 = 10000 ksi] alloy. The length of segment (1) is L1 = 80 in.
• Segment (2) is a copper [E2 = 17000 ksi] alloy. The length of segment (2) is L2 = 112 in.
When axial force P is applied, a strain gage attached to copper segment (2) measures a normal strain of ɛ2 = 1700 pin./in. in
longitudinal direction.
What is the total elongation of member ABC?
L2
(1)
d
Aluminum
В
(2)
Сopper
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