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Computer Engineering
Completes the codes on the line (highlighted in Yellow) for merge sort. 1 mergeSort(int[] A) 2 ( int n = A.length; 3 if (n < 2) return A; 4 int mid = n / 2; 5 int] left = new int[mid]; 6 int[) right = new int[n - mid]; 7 copy 0 to mid-1 of A into left 8 copy mid to n-1 of A into right 10 11 } 12 int([] merge(int[) A, int[] L, int[] R) { 13 int i = 0, j = 0, k = 0; 14 while (i < L.length && j < R.length) { 15 if (L[i] <= R[j]) { 16

Completes the codes on the line (highlighted in Yellow) for merge sort. 1 mergeSort(int[] A) 2 ( int n = A.length; 3 if (n < 2) return A; 4 int mid = n / 2; 5 int] left = new int[mid]; 6 int[) right = new int[n - mid]; 7 copy 0 to mid-1 of A into left 8 copy mid to n-1 of A into right 10 11 } 12 int([] merge(int[) A, int[] L, int[] R) { 13 int i = 0, j = 0, k = 0; 14 while (i < L.length && j < R.length) { 15 if (L[i] <= R[j]) { 16

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Completes the codes on the line (highlighted in Yellow) for merge sort. 1 mergeSort(int[] A) 2 { int n = A.length; 3 if (n < 2) return A; 4 int mid = n / 2; int] left = new int[mid]; 6 int] right = new int[n - mid]; copy 0 to mid-1 of A into left 8 copy mid to n-1 of A into right 9 10 11 } 12 int[] merge(int[] A, int[] L, int[] R) { 13 int i = 0, j = 0, k = 0; 14 while (i < L.length && j < R.length) { 15 if (L[i) <= R[j]) { 16 17 18 19 } else { 20 A[k] = R[j]; 21 j++; 22 k++; } 23 } 24 while (i < L.length) { 25 A[k] = L[i]; 26 i++; 27 k++;} 28 29 30 j++; 31 k++; } 32 return A; 33 }
Transcribed Image Text:Completes the codes on the line (highlighted in Yellow) for merge sort. 1 mergeSort(int[] A) 2 { int n = A.length; 3 if (n < 2) return A; 4 int mid = n / 2; int] left = new int[mid]; 6 int] right = new int[n - mid]; copy 0 to mid-1 of A into left 8 copy mid to n-1 of A into right 9 10 11 } 12 int[] merge(int[] A, int[] L, int[] R) { 13 int i = 0, j = 0, k = 0; 14 while (i < L.length && j < R.length) { 15 if (L[i) <= R[j]) { 16 17 18 19 } else { 20 A[k] = R[j]; 21 j++; 22 k++; } 23 } 24 while (i < L.length) { 25 A[k] = L[i]; 26 i++; 27 k++;} 28 29 30 j++; 31 k++; } 32 return A; 33 }
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