Complete this example-using flip-flop J-K (74LS73) Estado Futuro Output Estado Presente QA 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 QB 0 0 0 0 1 1 1 1 0 0 0 1 1 1 1 Input X 0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 Y 0 1 0 1 0 1 0 1 0 1 0 0 1 0 1 Flip Flop JA KA JB KB 20) 2(t+1) JK 0 0 0X -0 1. I 1 0 3 XO QA+ QB+ Z 11/1 10/1/ 01/1/ 00/1/ PISO 84 11 01/0 11/0 01/0 PISO 43 10 01/0 11/0 PISO #2 01 10/0/00/0 QAQB 00 PISO # 10/0/00/0 11/0 10/0 00/0

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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Draw a digital circuit using the minimum Boolean expression JA KA, JB KB, Z. (preferably in Logisim)

 

Complete this example-using flip-flop J-K (74LS73)
Estado Futuro Output
Estado
Presente
QA
0
0
0
0
0
0
0
0
1
1
1
1
1
1
1
1
QB
0
0
0
0
1
1
1
1
0
0
0
0
1
1
1
1
Input
X
0
0
1
1
0
0
1
1
0
0
1
1
0
0
1
1
Y
0
1
0
1
0
1
0
1
0
1
0
1
0
1
0
1
20)
0
shank
·0
JAN..
JA KA JB KB
1.
I
Flip Flop
Q(t+1)
0
.
0
JK
0X
XO
QA+
QB+
Z
11/1/
10/1/
01/1/
00/1/
PISO 84
11
01/0 11/0
01/0
PISO #3
10
01/0 11/0
PISO #2
01
10/0/00/0
QAQB
00
PISO #1
10/0/00/0
11/0 10/0 00/0
Transcribed Image Text:Complete this example-using flip-flop J-K (74LS73) Estado Futuro Output Estado Presente QA 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 QB 0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1 Input X 0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 Y 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 20) 0 shank ·0 JAN.. JA KA JB KB 1. I Flip Flop Q(t+1) 0 . 0 JK 0X XO QA+ QB+ Z 11/1/ 10/1/ 01/1/ 00/1/ PISO 84 11 01/0 11/0 01/0 PISO #3 10 01/0 11/0 PISO #2 01 10/0/00/0 QAQB 00 PISO #1 10/0/00/0 11/0 10/0 00/0
QAQB
XY
ОО
10
11
10
ОДОВ
XY
00
10
11
10
00
*
00
1
2
2
JA=
.
1
1
t
KA=
10
10
F
7
4
I
9
7
"
11 10
12
15
24
11 10
17
24
9
11
20
6
11
13
QAQB
XY
00
10
11
10
QAQB
XY
00
10
11
10
OD
I
OD
1
t
2
JB=
"
1
t
2
2
10
.
KB=
.
7
*
.
.
7
11
.
12
1
01 11 10
27
1
24
12
11
1
it
10
24
#
11
19
9
11
19
QAQB
XY
00
10
11
10
00
1
3
2
Z=
10
.
E
7
14
.
11 10
12
13
14
З
9
11
10
Transcribed Image Text:QAQB XY ОО 10 11 10 ОДОВ XY 00 10 11 10 00 * 00 1 2 2 JA= . 1 1 t KA= 10 10 F 7 4 I 9 7 " 11 10 12 15 24 11 10 17 24 9 11 20 6 11 13 QAQB XY 00 10 11 10 QAQB XY 00 10 11 10 OD I OD 1 t 2 JB= " 1 t 2 2 10 . KB= . 7 * . . 7 11 . 12 1 01 11 10 27 1 24 12 11 1 it 10 24 # 11 19 9 11 19 QAQB XY 00 10 11 10 00 1 3 2 Z= 10 . E 7 14 . 11 10 12 13 14 З 9 11 10
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