Complete the table by following the steps and procedures in Hypothesis Testing.A chemical company alleged that the average weight of its bag of chemical is 50 kilograms with astandard deviation of 0.9 kilograms. A sample of 29 bags was taken and revealed a mean weight of48.1 kilograms. Shall we accept the allegation of the chemical company? Use 0.01 as level ofsignificance.HYPOTHESIS TESTING1. Formulate the null and the Ho:alternative hypothesesIn symbol:Ho: μ = 50Ha: The average weight ofbag of chemical is not equalto 50 kilograms.In symbol:Ha:2. Specify the following:A. Level of SignificanceA.B. Types of Hypothesis Testing B. two tailed test[one-tailed test (left-tailed orright-tailed) or a two-tailedtest]3. Specify the following:A. The test statistic to be used.(t-test: one sample mean or t-test: two sample means)B. Find the Degree of FreedomFormula:df = n 1 (for one-sample B. df = n-1mean test)df = 16-1df = (₁ + n₂) 2 (for two-sample mean test)df = 15C. The critical or tabular value(teritical). (Can be found on C. 2.947the given table of TabularValue of T)4. Compute for the value of the Formula:test statistic (t computed) using(x-µ)√nthe data from the populationand the sample/s.Given:X-48.1H-n-29s-0.9Substitute the given to the formulaand solve:Decision:5. Make a decision.(Reject Ho and Accept Ha orAccept Ho and Reject Ha)6. State the conclusionConclusion:A.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A dietician wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Six randomly selected subjects were pretested, and then they took the mineral supplement of a 6 week period. The results are shown in the table below. Can it be concluded that the cholesterol level has changed at a significance level of 0.10? Use the P-value method with your calculator. Assume the variable is approximately normally distributed. You can use your calculator to answer this question but make sure that you clearly write the statements for the null and alternative hypothesis. Be sure that you thoroughly explain your final conclusion using the P-value method. Subject 1 2 3 4 5 6 Before 210 235 208 190 172 244 After 190 170 210 188 173 228
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? What is the test statistic, t? What is the P-value? State the conclusion for the test. b. Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean.
A random sample of 43 subjects who identified themselves as compulsive buyers was obtained and given a questionnaire. They had a mean questionnaire score of 0.52 with a standard deviation of 0.17. Test the claim that the population of self-identified compulsive buyers has a mean greater than the mean of 0.51 for the general population. Use a 0.05 significance level. State the null and alternative hypotheses. O B. Ho H= 0.51 O A. H, p= 0.51 H3 p> 0.51 H3 µ#0.51 ОС. Но н0.51 H3 p= 0.51 O D. Ho H=051 H, p<0,51
Perform the following hypothesis test: HO: µ = 10 H1: µ 10 The sample mean is 9.55, population standard deviation of 1.5 and a sample size of 51. Use a 5% significance level. What is the value of the test statistic? (Give your answer rounded to 2 decimals) (Be careful to make sure your + or - sign is correct)
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
Consider the following hypothesis test: Ho :µ = 17O Ha : µ + 170 A sample of 23 provided a sample mean of 182 and a sample standard deviation of 20. Find the value of the test statistic. Select one: O a. t= 0.60 O b. t = -0.60 O c. t= 2.88 O d. t=-2.88
The data in the accompanying table give the weights (in g) of randomly selected quarters that were minted after 1964. The quarters are supposed to have a median weight of 5.670 g. Use the sign test and a 0.01 significance level to test the claim that the median is equal to 5.670 g. Do quarters appear to be minted according to specifications? Click the icon to view the data. What are the null and alternative hypotheses? O A. Ho: Median weight = 5.670 g H₁: Median weight 5.670 g More Info OB. Ho: Median weight ≤ 5.670 g H₁: Median weight = 5.670 g O D. Ho: Median weight = 5.670 g H₁: Median weight # 5.670 g 0 Post-1964 Quarters 5.5863 5.5764 5.6582 5.5649 5.5844 5.7402 5.7367 5.6057 5.5995 5.6165 5.6448 5.5974 5.6609 5.6363 5.6352 5.5986 5.5797 5.5501 5.6238 5.6462 5.6423 5.7021 5.5481 5.7078 5.6055 5.5324 5.7417 5.6776 5.5924 5.5691 5.5666 5.7287 5.6312 5.6017 5.6626 5.6436 5.6634 5.6132 5.5441 5.6363 -
A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.01 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? A. Ho: M₁ = ₂ H₁: H₁ H₂ C. Ho: M₁ = H2 H₁: H₁ H₂ The test statistic, t, is (Round to two decimal places as needed.) B. Ho: H₁ H₂ H₁ H₁
Use five-step hypothesis testing for each of the following problems. Number each of the five steps. You may use the traditional method or the p-value method. 1) Science fiction novels average 250 pages in length. The average length of 8 randomly chosen novels written by I. M. Wordy was 265 pages in length with a standard deviation of 35. At are Wordy's novels significantly longer than the average science fiction novel? Use five-step hypothesis testing. 2) The average monthly cell phone bill was reported to be $50.07 by the U.S. Wireless Industry. Random Sampling of a large cell phone company found the following monthly cell phone charges (in dollars): At the 0.01 level of significance, can it be concluded that the average phone bill has…
Next Question Assume a significance level of a = 0.05 and use the given information to cd d (b) below. Original claim: More than 43% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0443. ..... a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. A. Fail to reject Ho because the P-value is greater than x. B. Reject H, because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 43%. B. There is not sufficient evidence to support the…
A magazine reported that at the top 50 business schools in a region, students studied an average of 14.4 hours. Set up a hypothesis test to try to prove that the mean number of hours studied at your school is different from the reported 14.4 hour benchmark. Complete parts (a) through (c) below. Question content area bottom Part 1 a. State the null and alternative hypotheses. Choose the correct answer below. A. H0: μ=14.4 H1: X≠14.4 B. H0: α≠14.4 H1: α=14.4 C. H0: α≠14.4 H1: β=14.4 D. H0: β=14.4 H1: β≠14.4 E. H0: μ≠14.4 H1: X=14.4 F. H0: μ=14.4 H1: μ≠14.4 G. H0: α=14.4 H1: β≠14.4 H. H0: β≠14.4 H1: β=14.4 I. H0: X≠14.4 H1: X=14.4 J. H0: α=14.4 H1: α≠14.4 K. H0: μ≠14.4 H1: μ=14.4 L. H0: X=14.4 H1: X≠14.4 Part 2 b. What is a Type I error for your test? A. Concluding that the mean…

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