Complete the table below for zero, first and simple second order reactions. [A]; vs. t 1/s 1/[A];= kt+ + 1/[A]o 1/[A]; vs. t In[A];= -kt + In[A]o k, 1/[A] [A]t=-kt + [A]o In [A], vs. t [A];= kt+ [A]o rate = k/[A] Rate law Units for k Integrated rate law in straight-line form Plot for straight line Slope, y intercept -K, [A], 1/[A]+= -kt + 1/[A]o mol/L's rate = k k, [A], Zero Order rate = K[A] L/mol-s rate = K[A]² -k, In [A], L²/mol².s First Order mol²/L².s In[A];=kt + In[A]o -k, 1/[A] [A]² vs. t k, In [A], Second Order
Complete the table below for zero, first and simple second order reactions. [A]; vs. t 1/s 1/[A];= kt+ + 1/[A]o 1/[A]; vs. t In[A];= -kt + In[A]o k, 1/[A] [A]t=-kt + [A]o In [A], vs. t [A];= kt+ [A]o rate = k/[A] Rate law Units for k Integrated rate law in straight-line form Plot for straight line Slope, y intercept -K, [A], 1/[A]+= -kt + 1/[A]o mol/L's rate = k k, [A], Zero Order rate = K[A] L/mol-s rate = K[A]² -k, In [A], L²/mol².s First Order mol²/L².s In[A];=kt + In[A]o -k, 1/[A] [A]² vs. t k, In [A], Second Order
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Solve correctly please.
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![Complete the table below for zero, first and simple second order reactions.
[A]t vs. t
1/s
1/[A]t = kt + 1/[A]o
In[A] = -kt + In[A]o
[A]t = -kt + [A]o
[A]t = kt+ [A]o
Rate law
Units for k
1/[A]; vs. t
k, 1/[A],
In [A]; vs. t
rate = k/[A]
Integrated rate law in
straight-line form
Plot for straight line
Slope, y intercept
-K, [A],
1/[A]t-kt + 1/[A]o
mol/L's
rate = k
k, [A]
Zero Order
rate=
K[A]
L/mol-s
rate = K[A]²
-k, In [A],
L²/mol²-s
First Order
mol²/L².s
In[A]+= kt + In[A]o
-k, 1/[A],
[A]² vs. t
k, In [A],
Second Order](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feeb37bd8-ce90-4f67-9710-8ab0b147d518%2Fd1dffa2d-990a-46d8-bf7b-f2fc1fa16be6%2Fzwqlccg_processed.png&w=3840&q=75)
Transcribed Image Text:Complete the table below for zero, first and simple second order reactions.
[A]t vs. t
1/s
1/[A]t = kt + 1/[A]o
In[A] = -kt + In[A]o
[A]t = -kt + [A]o
[A]t = kt+ [A]o
Rate law
Units for k
1/[A]; vs. t
k, 1/[A],
In [A]; vs. t
rate = k/[A]
Integrated rate law in
straight-line form
Plot for straight line
Slope, y intercept
-K, [A],
1/[A]t-kt + 1/[A]o
mol/L's
rate = k
k, [A]
Zero Order
rate=
K[A]
L/mol-s
rate = K[A]²
-k, In [A],
L²/mol²-s
First Order
mol²/L².s
In[A]+= kt + In[A]o
-k, 1/[A],
[A]² vs. t
k, In [A],
Second Order
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