Complete the Table based on the picture (Heat Neutralization between a strong acid and a strong base) In calculating the mass of water in the mixture, assume that the volume of the solution is mainly from water and that the volume of HCl and NaOH are negligible. Also, assume that the density of water is 1 g/mL. Volume of HCl solution = 100 mL Volume of NaOH solution = 100 mL Total Volume of mixture= 200 mL Mass of Water in the mixture= Initial temperature of Water= 20.0°C Final Temperature of Water = 23.41°C q water = q reaction= Molarity of HCl solution= 0.500 M Molarity of NaOH solution = 0.500M moles of HCl= moles of NaOH= Limiting Reactant= moles of limiting reactant= ΔH reaction=
Complete the Table based on the picture
(Heat Neutralization between a strong acid and a strong base)
In calculating the mass of water in the mixture, assume that the volume of the solution is mainly from water and that the volume of HCl and NaOH are negligible.
Also, assume that the density of water is 1 g/mL.
Volume of HCl solution = 100 mL
Volume of NaOH solution = 100 mL
Total Volume of mixture= 200 mL
Mass of Water in the mixture=
Initial temperature of Water= 20.0°C
Final Temperature of Water = 23.41°C
q water =
q reaction=
Molarity of HCl solution= 0.500 M
Molarity of NaOH solution = 0.500M
moles of HCl=
moles of NaOH=
Limiting Reactant=
moles of limiting reactant=
ΔH reaction=

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Limiting Reactant=
moles of limiting reactant=
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