Complete the program below which counts the number of capital letters in word? count =0 for char in word: count = count + 1 if char.upper(): if char.isupper() : if char >= "A" and char <= "z": if char.islower() : if word.isupper():
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- char letter1; char letter2; letter1 = 'y'; while (letter1 <= 'z') { letter2 = 'a'; while (letter2 <= 'c'){ System.out.print("" + letter1 + letter2 + " "); ++letter2; } ++letter1; } For this code why did we use "" before and after in this line? System.out.print("" + letter1 + letter2 + " "); ++letter2; What if we don't use the blank quotation would the output be same? because I don't see the reason for putting those quotation mark.Question 1 Complete the program below which counts the number of capital letters in word? count Not yet for char in word: answered Marked out of 3.00 count count + 1 P Flag question if char.upper(): if word.isupper(): if char >= "A" and char <= "z" : if char.islower(): if char.isupper():Magic Number Programming: Magic program ask user to enter three integers by the user, the three integers represent left bound, right bound and arbitrary digit 'm', where left bound is less than right bound. Program should print all magic numbers in the given range that doesn't contain digit 'm'. The number is magic if its every digit is larger than the sum of digits which are on the right side of that digit. For example, 94210 is magic number because 1 > 0, 2 > 1+0, 4>2+1+0, and 9 > 4+2+1+0. Write a complete C program that Call only One Function (magic_numbers) that will print all magic numbers excluding a given digit 'm' that also entered by user ? Input Sample : Enter Left bound: 740 Enter Right bound:850 Enter digit to exclude it:2 Output sample: Magic Numbers in Range Left=740, Right=850 with exclude digit m= 2 are: 740 741 750 751 760 810 830 831 840 841 843 850 Your function prototype is like this: void magic_numbers(int left, int right, int digit) ;
- Questioin: Hidden Secret Problem! In this problem, you are given two names, you have to find whether one name is hidden into another. The restrictions are: You can change some uppercase letters to lower case and vice versa. You can add/remove spaces freely. You can permute the letters. And if both the names match exactly, then you can say that one name is hidden into another. Input Input starts with an integer T (≤ 100), denoting the number of test cases. Each case starts with two lines. Each line contains a name consists of upper/lower case English letters and spaces. You can assume that the length of any name is between 1 and 100(inclusive). Output For each case, print the case number and Yes if one name is hidden into another. Otherwise print No. Sample Input Output 3 Tom Marvolo Riddle I am Lord Voldemort I am not Harry Potter Hi Pretty Roar to man Harry and Voldemort Tom and Jerry and Harry Case 1: Yes Case 2: Yes Case 3: No And I want…Zybook Lab highway_number = int(input())if(highway_number>=1 and highway_number<=99): if(highway_number%2==0): print("I-"+str(highway_number),"is primary, going east/west.") else: print("I-"+str(highway_number),"is primary, going north/south.") elif(highway_number>=100 and highway_number<=999): highway_number_string = str(highway_number) length = len(highway_number_string) rightmost_digits = int(highway_number_string[length-2:length]) if(rightmost_digits==0): print(highway_number,"is not a valid interstate highway number.") elif(rightmost_digits%2==0): print("I-"+str(highway_number),"is auxiliary, serving I-",rightmost_digits,"going east/west.") else: print("I-"+str(highway_number),"is auxiliary, serving I-",rightmost_digits,"going north/south.")else: print(highway_number,"is not a valid interstate highway number.") i am getting whitespace error on output : I-290 is auxiliary, serving I- 90 going…The program segment has errors. Find as many as you can. // This code should average a set of numbers. int numCount, total;double average; cout << "How many numbers do you want to average? "; cin >> numCount;for (int count = 0; count < numCount; count++) {int num;cout << "Enter a number: "; cin >> num;total += num; count++;}average = total / numCount;cout << "The average is << average << end1;
- All coding is done in Java. I am using IntelliJ Idea if it helps. 12. Bar Chart Write a program that asks the user to enter today's sales for five stores. The program should display a bar chart comparing each store's sales. Create each bar in the bar chart by displaying a row of asterisks. Each asterisk should represent $100 of sales. Example: Enter today's sales for store 1: 1000 [Enter] Enter today's sales for store 2: 1200 [Enter] Sales Bar Chart Store 1: ********** Store 2: ************What will the value of the answer variable be after the code segment below has been run. bool answer ; int number1 = 8, number4 = 16; answer = number1 < number4 ;Complete the loop so that it displays all mountains that are over 15000 feet. The blank ____ on the code below indicates where your statement will be placed. var mountains = ["Mount Everest" : 29029, "Nanga Parbat" : 26660, "Kanlaon" : 8087, "Pico de Orizaba" : 18491, "Sabalan" : 15784]for ____ { if elevation > 15000 { print("\(mountain): \(elevation) feet.") } }
- Credit Card Number Check. The last digit of a credit card number is the check digit, which protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16:• Starting from the rightmost digit, form the sum of every other digit. For example, if thecredit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23.• Double each of the digits that were not included in the preceding step. Add all digits ofthe resulting numbers. For example, with the number given above, doubling the digits,starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these valuesyields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27.• Add the sums of the two preceding steps. If the last digit of the result is 0, the number isvalid. In our case, 23 + 27 = 50, so the number is valid.Write a program that implements this…Credit Card Number Check. The last digit of a credit card number is the check digit, which protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16:• Starting from the rightmost digit, form the sum of every other digit. For example, if thecredit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23.• Double each of the digits that were not included in the preceding step. Add all digits ofthe resulting numbers. For example, with the number given above, doubling the digits,starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these valuesyields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27.• Add the sums of the two preceding steps. If the last digit of the result is 0, the number isvalid. In our case, 23 + 27 = 50, so the number is valid.Write a program that implements this…Python Assignment: In India McDonald's has the n number of customers and they are famous for their taste and quality so they plan to Organise the challenge for foody people. What is the challenge is?| you have taken a food challenge from the Chef and now you have to eat directly the Y burgers. You will eat as follows: At the first minute you will eat exactly the X burgers and every minute after that you will eat twice the number of burgers you ate the minute before. As you can get tired of food, Chef also lets you take a break from eating for one minute. When you start eating again after a break, your food streaks are reset, which means that in the first minute after the break you will eat X burgers and every minute after that you will eat the burgers you ate twice the last minute. Allow a1, a2, ., let it be your meal length in minutes. The cook needs to have all the ai different in pairs. Get the minimum number of minutes you need to eat Y burgers directly or decide that it is not…