- Complete the partition() method ray so that they are partitioned into segments containing the elements BLUE, and GREEN, respectively. You may assume the existence of methods isRed(), isWhite(). tc., having the obvious interpretations, plus swap(), which is such that the call swap(ary,p,g) waps the elements in locations p and q of array ary[]. The intent is for the invariant of the loop to be as suggested by this picture, which says that al elements in a[0..i) are RED, all elements in a[i..j) are WHITE, all elements in a[k..m)ar BLUE, and all elements in a [m..N) are GREEN.
- Complete the partition() method ray so that they are partitioned into segments containing the elements BLUE, and GREEN, respectively. You may assume the existence of methods isRed(), isWhite(). tc., having the obvious interpretations, plus swap(), which is such that the call swap(ary,p,g) waps the elements in locations p and q of array ary[]. The intent is for the invariant of the loop to be as suggested by this picture, which says that al elements in a[0..i) are RED, all elements in a[i..j) are WHITE, all elements in a[k..m)ar BLUE, and all elements in a [m..N) are GREEN.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![2. Complete the partition() method below, the goal of which is to rearrange the elements of a c
array so that they are partitioned into segments containing the elements that are RED, WHITE
BLUE, and GREEN, respectively. You may assume the existence of methods isRed (), isWhite().
etc., having the obvious interpretations, plus swap(), which is such that the call swap(ary,p,q)
swaps the elements in locations
and
of array ary [).
The intent is for the invariant of the loop to be as suggested by this picture, which says that all
elements in a[0..i) are RED, all elements in a[i..j) are WHITE, all elements in a[k..m)are
BLUE, and all elements in a [m..N) are GREEN.
i
k
+-
a | RED
WHITE I
I BLUE I GREEN |
?
/* Rearranges the elements of the given array as described above.
*/
public static void partition (T[] a)
final int N = a.length;
int i =,
j -
-----
----
------
) {
while (](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c6c9736-9c57-41f2-81e3-c373745c6be6%2Fac096bb7-212b-4bdb-8e78-7477d51d66b8%2Fszno4z_processed.png&w=3840&q=75)
Transcribed Image Text:2. Complete the partition() method below, the goal of which is to rearrange the elements of a c
array so that they are partitioned into segments containing the elements that are RED, WHITE
BLUE, and GREEN, respectively. You may assume the existence of methods isRed (), isWhite().
etc., having the obvious interpretations, plus swap(), which is such that the call swap(ary,p,q)
swaps the elements in locations
and
of array ary [).
The intent is for the invariant of the loop to be as suggested by this picture, which says that all
elements in a[0..i) are RED, all elements in a[i..j) are WHITE, all elements in a[k..m)are
BLUE, and all elements in a [m..N) are GREEN.
i
k
+-
a | RED
WHITE I
I BLUE I GREEN |
?
/* Rearranges the elements of the given array as described above.
*/
public static void partition (T[] a)
final int N = a.length;
int i =,
j -
-----
----
------
) {
while (
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