Complete the missing ones: (those highlighted ones) Integrate: [ tan5 3x sec6 3x dx [ tan³ 3x sec 3x dx = [ tan¹ 3x sec³ 3x tan 3x sec 3x dx = [[ITEM E1) sec³ 3x tan 3x sec 3x dx = [UTEM E2) sec³ 3x tan 3x sec 3x dx = SUTEM = [sec 3x tan 3x sec 3x dx - 2 f sec² 3x tan 3x sec 3x dx + [sec³ 3x tan 3x sec 3x dx Let u = sec 3x {ITEM E4} (ITEM E3) sec5 3x tan 3x sec 3x dx du = [u³y + (ITEM E5) + fus du 3 3 sec 10 3x 10 +{ITEM E6} + {ITEM E7) + C
Complete the missing ones: (those highlighted ones) Integrate: [ tan5 3x sec6 3x dx [ tan³ 3x sec 3x dx = [ tan¹ 3x sec³ 3x tan 3x sec 3x dx = [[ITEM E1) sec³ 3x tan 3x sec 3x dx = [UTEM E2) sec³ 3x tan 3x sec 3x dx = SUTEM = [sec 3x tan 3x sec 3x dx - 2 f sec² 3x tan 3x sec 3x dx + [sec³ 3x tan 3x sec 3x dx Let u = sec 3x {ITEM E4} (ITEM E3) sec5 3x tan 3x sec 3x dx du = [u³y + (ITEM E5) + fus du 3 3 sec 10 3x 10 +{ITEM E6} + {ITEM E7) + C
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter1: Systems Of Linear Equations
Section1.3: Applications Of Systems Of Linear Equations
Problem 13E: Use sin0=0, sin2=1, and sin=0 to estimate sin3.
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pls ans asap thank u
![Complete the missing ones: (those highlighted ones)
Integrate:
[ tan5 3x sec6 3x dx
[ tan³ 3x sec 3x dx = [ tan¹ 3x sec³ 3x tan 3x sec 3x dx
= [[ITEM E1) sec³ 3x tan 3x sec 3x dx
= [UTEM E2) sec³ 3x tan 3x sec 3x dx
= SUTEM
= [sec 3x tan 3x sec 3x dx - 2 f sec² 3x tan 3x sec 3x dx + [sec³ 3x tan 3x sec 3x dx
Let u = sec 3x
{ITEM E4}
(ITEM E3) sec5 3x tan 3x sec 3x dx
du
= [u³y + (ITEM E5) + fus du
3
3
sec 10 3x
10
+{ITEM E6} + {ITEM E7) + C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cdb4c9c-3700-4137-91b7-84cf3024b551%2F41e8bd81-12f8-497e-b221-c211f793dcb2%2F3tinn07_processed.png&w=3840&q=75)
Transcribed Image Text:Complete the missing ones: (those highlighted ones)
Integrate:
[ tan5 3x sec6 3x dx
[ tan³ 3x sec 3x dx = [ tan¹ 3x sec³ 3x tan 3x sec 3x dx
= [[ITEM E1) sec³ 3x tan 3x sec 3x dx
= [UTEM E2) sec³ 3x tan 3x sec 3x dx
= SUTEM
= [sec 3x tan 3x sec 3x dx - 2 f sec² 3x tan 3x sec 3x dx + [sec³ 3x tan 3x sec 3x dx
Let u = sec 3x
{ITEM E4}
(ITEM E3) sec5 3x tan 3x sec 3x dx
du
= [u³y + (ITEM E5) + fus du
3
3
sec 10 3x
10
+{ITEM E6} + {ITEM E7) + C
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