complete the leve1 the 5. DOUBLE-RODDED LEVELING. Set up and for a double-rodded line from BM45 to BM46. following rod readings H refers to stations along the stations along notes In high route and to the low route: BS on BM45=2.238, FS on TP1(H) 0.703, FS on TP1 (L)=1.252, BS on FS on TP 2 (H) =1.173, FS on rp1(H)=2.855. BS on TP1(L)= 3. 402.
complete the leve1 the 5. DOUBLE-RODDED LEVELING. Set up and for a double-rodded line from BM45 to BM46. following rod readings H refers to stations along the stations along notes In high route and to the low route: BS on BM45=2.238, FS on TP1(H) 0.703, FS on TP1 (L)=1.252, BS on FS on TP 2 (H) =1.173, FS on rp1(H)=2.855. BS on TP1(L)= 3. 402.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please recheck and provide clear and complete step-by-step solutions in scanned handwriting or computerized output. Thank you.

Transcribed Image Text:complete the level
In
5. DOUBLE-RODDED
LEVELING. Set
up and
the
for a double-rodded line from BM45 to BM46.
following rod readings H refers to stations along the
stations along
notes
high
route
and
to
the
low
route:
BS
on
FS on TP1 (L) =1.252, BS on
FS on TP2 (H)=1.173, FS on
BM45=2.238,
FS on TP1 (H) 0.703,
TP1 (H) = 2.855, BS on TP1 (L)= 3.402, FS on TP 2 (H) =1.173, FS on
TP 2 (L) =1.558, BS on TP 2 (H) = 2.542, , FS on
TP 3 (H) =1.339, FS on TP 3 (L)=1.660, BS on TP 3 (H) = 2.390, BS on
and FS on BM46=1.015 meters. Assume that the
customarY
%3D
%3D
BS on TP 2 (L) 2.932,
%3D
%|
TP3 (L) = 2.711,
of
arithmetic check.
%3D
elevation
BM45
is 524.550 m.
Perform
the
Expert Solution
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