Complete the following table, filling in the missing entries and replacing each question mark with the appropriate integer. Use the following units: K = 210 (kilo), M = 220 (mega), G = 230 (giga), T= 240 (tera), P = 250 (peta), or E = 200 (exa). Drag the appropriate labels to their respective targets. Reset Help 1 2 3 8 10 12 16 20 24 28 30 32 40 48 56 60 63 64 100 120 127 128 255 256 511 512 1023 | 1024 2047 2048 4096 8192 16,384 к K M G P E Number of virtual address bits (n) Number of virtual addresses (N) Largest possible virtual address 2 =( -1= O 2 -1€ 232 – 1€ 2 - 1€ 2 -1€ 8 2 -1=( 2 = 64 K 1 2 =| G – 1 2 = 256 T 1 64 2 = 1

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Complete the following table, filling in the missing entries and replacing each question mark with the appropriate integer. Use the following units: K = 210 (kilo), M = 220 (mega), G = 230 (giga), T = 240 (tera), P = 250 (peta), or E = 260 (exa).
Drag the appropriate labels to their respective targets.
Reset
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1
2
3
8
10
12
16
20
24
28
30
32
40
48
56
60
63
64
100
120
127
128
255
256
511
512
1023
1024
2047
2048
4096
8192
16,384
K
M
G
P
E
Number of
virtual addresses (N)
Number of
virtual address bits (n)
Largest possible virtual address
8
2 =(
2 - 1=(
2 -1€
232 – 1€
2 -1€
2 =
64 K
1
2 =|
G – 1
1
2 = 256 T
64
2
2 -1€
1
Transcribed Image Text:Complete the following table, filling in the missing entries and replacing each question mark with the appropriate integer. Use the following units: K = 210 (kilo), M = 220 (mega), G = 230 (giga), T = 240 (tera), P = 250 (peta), or E = 260 (exa). Drag the appropriate labels to their respective targets. Reset Help 1 2 3 8 10 12 16 20 24 28 30 32 40 48 56 60 63 64 100 120 127 128 255 256 511 512 1023 1024 2047 2048 4096 8192 16,384 K M G P E Number of virtual addresses (N) Number of virtual address bits (n) Largest possible virtual address 8 2 =( 2 - 1=( 2 -1€ 232 – 1€ 2 -1€ 2 = 64 K 1 2 =| G – 1 1 2 = 256 T 64 2 2 -1€ 1
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