The image is an ANOVA summary table for a two-factor fixed-effects ANOVA. It examines four levels of factor A (school) and three levels of factor B (curriculum design), with each cell containing 15 students.The table displays the analysis with the following columns:- **Source**: The factors and interactions examined, including Error and Total.- **SS** (Sum of Squares): Variability attributed to each source.- **df** (Degrees of Freedom): Needed to calculate the mean square and F-value.- **MS** (Mean Square): SS divided by df, indicating variability per unit of degrees of freedom.- **F**: The F-ratio calculated for each source.- **P**: The probability value for testing significance.Values given are:- **A** (Factor A: School): - SS = 2832.6 - MS = 2832.6 - F = 2.832 - P = 0.04- **B** (Factor B: Curriculum Design): - SS = 3125.9 - MS = 1041.96 - F = 1.946 - P = 0.146- **A x B** (Interaction): - SS = 8974.6 - MS = 2991.53 - F = 1.863 - P = 0.09- **Error**: - SS = 134904- **TOTAL**: - SS = 153825.6This table helps in determining whether there are significant differences among the means of the different levels of the factors and their interaction.

For two way ANOVA, ANOVA table is: Sum of squares Degrees of freedom Mean square F-value p-value A SSA k-1 MSA= SSA/(K-1) MSA/MSE Calculated from F-table B SSB l-1 MSB= SSB/(l-1) MSB/MSE Calculated from F-table AB SSAB (k-1)(l-1) MSAB =SSAB /(k-1)(l-1) MSAB/MSE Calculated from F-table Error SSE N-(kl) MSE= SSE/N-(kl) Total SST N-1 There are four levels of factor A and three level of factor B and each cell includes 15 cells. k=4 l=3 N=15 Sum of squares Degrees of freedom Mean square F-value p-value A 6821.1 3 2273.7 2.832 0.04 B 3125.9 2 1562.9 1.946 0.146 AB 8974.6 6 1495.8 1.863 0.09 Error 134904 3 44968 Total 153825.6 14 SSA is calculated as: SST - (SSB+SSAB+SSE)

Math

Statistics

Complete the following ANOVA summary lable for a two-factor fixed-effecis ANOVA, where there are four levels of factor A (school) and three levels of factor B (curriculum design). Cach cell includes 15 students. SS df MS Source 2.832 0.04 B 3125.9 1.946 0.146 Ax B 8974.6 1.863 0.09 Crror 134904 TОTAL 153825.6

Complete the following ANOVA summary lable for a two-factor fixed-effecis ANOVA, where there are four levels of factor A (school) and three levels of factor B (curriculum design). Cach cell includes 15 students. SS df MS Source 2.832 0.04 B 3125.9 1.946 0.146 Ax B 8974.6 1.863 0.09 Crror 134904 TОTAL 153825.6

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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