Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Lesson: Plotting Linear Equations
#### Step 1: Complete the Chart and Plot Points
**Equation**:
\[ 3x - 2y = 12 \]
**Chart**:
| x | y | (x, y) |
|---|----|--------|
| 0 | -1 | (0, -1) |
| 2 | | |
#### Calculation to Complete the Chart:
To find the value of \( y \) when \( x = 2 \):
\[
3(2) - 2y = 12
\]
\[
6 - 2y = 12
\]
\[
-2y = 6
\]
\[
y = -3
\]
So, when \( x = 2 \), \( y = -3 \).
The completed chart is:
| x | y | (x, y) |
|---|-----|----------|
| 0 | -1 | (0, -1) |
| 2 | -3 | (2, -3) |
#### Step 2: Graph the Linear Equation
- **Grid**: The provided grid has an x-axis and a y-axis, with each axis ranging from -5 to 5.
- **Plot Points**:
- The first point is (0, -1).
- The second point is (2, -3).
**Instructions**:
1. Locate the first point (0, -1) on the graph. On the x-axis, go to 0, and on the y-axis, go down to -1.
2. Locate the second point (2, -3) on the graph. From the origin, move right to 2 on the x-axis and then go down to -3 on the y-axis.
3. Draw a straight line through these two points. This line represents the linear equation \( 3x - 2y = 12 \).
#### Step 3: Graph the Linear Equation \( y = 3 \)
This is a horizontal line where y is always equal to 3, regardless of the value of x.
1. Locate y = 3 on the y-axis.
2. Draw a straight line parallel to the x-axis passing through y = 3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadaf492b-253f-4d8c-b0e9-8fd15c842032%2F8c9900b1-306d-4217-bc9e-700b140b8699%2Fye9bxz6.jpeg&w=3840&q=75)
Transcribed Image Text:### Lesson: Plotting Linear Equations
#### Step 1: Complete the Chart and Plot Points
**Equation**:
\[ 3x - 2y = 12 \]
**Chart**:
| x | y | (x, y) |
|---|----|--------|
| 0 | -1 | (0, -1) |
| 2 | | |
#### Calculation to Complete the Chart:
To find the value of \( y \) when \( x = 2 \):
\[
3(2) - 2y = 12
\]
\[
6 - 2y = 12
\]
\[
-2y = 6
\]
\[
y = -3
\]
So, when \( x = 2 \), \( y = -3 \).
The completed chart is:
| x | y | (x, y) |
|---|-----|----------|
| 0 | -1 | (0, -1) |
| 2 | -3 | (2, -3) |
#### Step 2: Graph the Linear Equation
- **Grid**: The provided grid has an x-axis and a y-axis, with each axis ranging from -5 to 5.
- **Plot Points**:
- The first point is (0, -1).
- The second point is (2, -3).
**Instructions**:
1. Locate the first point (0, -1) on the graph. On the x-axis, go to 0, and on the y-axis, go down to -1.
2. Locate the second point (2, -3) on the graph. From the origin, move right to 2 on the x-axis and then go down to -3 on the y-axis.
3. Draw a straight line through these two points. This line represents the linear equation \( 3x - 2y = 12 \).
#### Step 3: Graph the Linear Equation \( y = 3 \)
This is a horizontal line where y is always equal to 3, regardless of the value of x.
1. Locate y = 3 on the y-axis.
2. Draw a straight line parallel to the x-axis passing through y = 3.
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