Complete the chart 3x-2y% D %3D

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Lesson: Plotting Linear Equations

#### Step 1: Complete the Chart and Plot Points

**Equation**: 
\[ 3x - 2y = 12 \]

**Chart**:

| x | y  | (x, y) |
|---|----|--------|
| 0 | -1 | (0, -1) |
| 2 |    |        |

#### Calculation to Complete the Chart:

To find the value of \( y \) when \( x = 2 \):
\[
3(2) - 2y = 12
\]
\[
6 - 2y = 12
\]
\[
-2y = 6
\]
\[
y = -3
\]

So, when \( x = 2 \), \( y = -3 \).

The completed chart is:

| x |  y  | (x, y)   |
|---|-----|----------|
| 0 |  -1 | (0, -1)  |
| 2 |  -3 | (2, -3)  |

#### Step 2: Graph the Linear Equation

- **Grid**: The provided grid has an x-axis and a y-axis, with each axis ranging from -5 to 5.
- **Plot Points**:
  - The first point is (0, -1). 
  - The second point is (2, -3).

**Instructions**:
1. Locate the first point (0, -1) on the graph. On the x-axis, go to 0, and on the y-axis, go down to -1.
2. Locate the second point (2, -3) on the graph. From the origin, move right to 2 on the x-axis and then go down to -3 on the y-axis.
3. Draw a straight line through these two points. This line represents the linear equation \( 3x - 2y = 12 \).

#### Step 3: Graph the Linear Equation \( y = 3 \)

This is a horizontal line where y is always equal to 3, regardless of the value of x. 
1. Locate y = 3 on the y-axis.
2. Draw a straight line parallel to the x-axis passing through y = 3.
Transcribed Image Text:### Lesson: Plotting Linear Equations #### Step 1: Complete the Chart and Plot Points **Equation**: \[ 3x - 2y = 12 \] **Chart**: | x | y | (x, y) | |---|----|--------| | 0 | -1 | (0, -1) | | 2 | | | #### Calculation to Complete the Chart: To find the value of \( y \) when \( x = 2 \): \[ 3(2) - 2y = 12 \] \[ 6 - 2y = 12 \] \[ -2y = 6 \] \[ y = -3 \] So, when \( x = 2 \), \( y = -3 \). The completed chart is: | x | y | (x, y) | |---|-----|----------| | 0 | -1 | (0, -1) | | 2 | -3 | (2, -3) | #### Step 2: Graph the Linear Equation - **Grid**: The provided grid has an x-axis and a y-axis, with each axis ranging from -5 to 5. - **Plot Points**: - The first point is (0, -1). - The second point is (2, -3). **Instructions**: 1. Locate the first point (0, -1) on the graph. On the x-axis, go to 0, and on the y-axis, go down to -1. 2. Locate the second point (2, -3) on the graph. From the origin, move right to 2 on the x-axis and then go down to -3 on the y-axis. 3. Draw a straight line through these two points. This line represents the linear equation \( 3x - 2y = 12 \). #### Step 3: Graph the Linear Equation \( y = 3 \) This is a horizontal line where y is always equal to 3, regardless of the value of x. 1. Locate y = 3 on the y-axis. 2. Draw a straight line parallel to the x-axis passing through y = 3.
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