Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 8 of 10:**
**Complete the balanced neutralization equation for the reaction below:**
\[ \text{KOH(aq) + H}_2\text{SO}_4\text{(aq)} \rightarrow \]
**Additional Instructions:**
- Use the provided keypad to input chemical symbols and formulas.
- Ensure the equation is balanced with respect to the number of atoms on both sides.
**Explanation:**
This question asks you to balance the neutralization reaction between potassium hydroxide (KOH) and sulfuric acid (H₂SO₄).
**Steps to Balance:**
1. **Identify the Products:**
- The reaction between KOH and H₂SO₄ is a neutralization reaction, typically forming salt and water. The salt formed is potassium sulfate (K₂SO₄), and water (H₂O) is also a product.
2. **Write the Unbalanced Equation:**
\[ \text{KOH(aq) + H}_2\text{SO}_4\text{(aq)} \rightarrow \text{K}_2\text{SO}_4\text{(aq) + H}_2\text{O(l)} \]
3. **Balance the Equation:**
- Balance the potassium (K) atoms: There are 2 potassium atoms in K₂SO₄, so you need 2 KOH.
- Balance the hydrogen (H) atoms: There are 2 hydrogens in H₂O and 2 hydrogens in H₂SO₄, so 2 molecules of H₂O are needed.
- Balance the oxygen (O) atoms: Ensure the number of oxygen atoms are equal on both sides.
4. **Final Balanced Equation:**
\[ 2\text{KOH(aq) + H}_2\text{SO}_4\text{(aq)} \rightarrow \text{K}_2\text{SO}_4\text{(aq) + 2H}_2\text{O(l)} \]
This balanced equation ensures that there are equal numbers of each type of atom on both sides of the reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7bd06d49-1f03-4d83-9ba1-5526279a5db3%2F7639350e-7af9-4031-8dda-aab47c113a96%2Fuvpa35f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 8 of 10:**
**Complete the balanced neutralization equation for the reaction below:**
\[ \text{KOH(aq) + H}_2\text{SO}_4\text{(aq)} \rightarrow \]
**Additional Instructions:**
- Use the provided keypad to input chemical symbols and formulas.
- Ensure the equation is balanced with respect to the number of atoms on both sides.
**Explanation:**
This question asks you to balance the neutralization reaction between potassium hydroxide (KOH) and sulfuric acid (H₂SO₄).
**Steps to Balance:**
1. **Identify the Products:**
- The reaction between KOH and H₂SO₄ is a neutralization reaction, typically forming salt and water. The salt formed is potassium sulfate (K₂SO₄), and water (H₂O) is also a product.
2. **Write the Unbalanced Equation:**
\[ \text{KOH(aq) + H}_2\text{SO}_4\text{(aq)} \rightarrow \text{K}_2\text{SO}_4\text{(aq) + H}_2\text{O(l)} \]
3. **Balance the Equation:**
- Balance the potassium (K) atoms: There are 2 potassium atoms in K₂SO₄, so you need 2 KOH.
- Balance the hydrogen (H) atoms: There are 2 hydrogens in H₂O and 2 hydrogens in H₂SO₄, so 2 molecules of H₂O are needed.
- Balance the oxygen (O) atoms: Ensure the number of oxygen atoms are equal on both sides.
4. **Final Balanced Equation:**
\[ 2\text{KOH(aq) + H}_2\text{SO}_4\text{(aq)} \rightarrow \text{K}_2\text{SO}_4\text{(aq) + 2H}_2\text{O(l)} \]
This balanced equation ensures that there are equal numbers of each type of atom on both sides of the reaction.
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