Complete Part B - this is a ratio and proportion problem (from basic math skills) Part B The table contains the planets in our solar system in order of their average distance from the Sun and their corresponding diameters. The first step in creating a model of the solar system is to scale these large diameters into smaller, more manageable numbers. Eventually, we'll represent these numbers using circles drawn on paper. Diameter (km) Scaled Diameter (cm) Mercury 4879 Increasing Distance from the Sun → Venus Jupiter Earth 12.756 Mars 6792 12.104 142.984 3.5 1.9 Saturn 120,536 12756 km (the diameter of Earth 6792 km (the diameter of Mars) 3.5 cm (the proportional size) X Uranus 51,118 Neptune 49,528 Here is an example of how to solve for the empty boxes - First you set up each problem with this comparison - 12,756 km (the diameter of the Earth) is equivalent to 3.5 centimeters - so that is your ratio: Then you "cross multiply and divide" - 3.5 cm x 6792 km = 1.9 cm (notice that the km's cancel out) 12756 km Solve the remaining proportions (scaled diameters) and complete the table. If you need help with the math, meet me in a help session - it's pretty quick to complete (once you realize what they are really asking). This diagram shows you how large they are compared to one another - it does NOT accurately indicate the distances between the Sun and each of the planets.
Complete Part B - this is a ratio and proportion problem (from basic math skills) Part B The table contains the planets in our solar system in order of their average distance from the Sun and their corresponding diameters. The first step in creating a model of the solar system is to scale these large diameters into smaller, more manageable numbers. Eventually, we'll represent these numbers using circles drawn on paper. Diameter (km) Scaled Diameter (cm) Mercury 4879 Increasing Distance from the Sun → Venus Jupiter Earth 12.756 Mars 6792 12.104 142.984 3.5 1.9 Saturn 120,536 12756 km (the diameter of Earth 6792 km (the diameter of Mars) 3.5 cm (the proportional size) X Uranus 51,118 Neptune 49,528 Here is an example of how to solve for the empty boxes - First you set up each problem with this comparison - 12,756 km (the diameter of the Earth) is equivalent to 3.5 centimeters - so that is your ratio: Then you "cross multiply and divide" - 3.5 cm x 6792 km = 1.9 cm (notice that the km's cancel out) 12756 km Solve the remaining proportions (scaled diameters) and complete the table. If you need help with the math, meet me in a help session - it's pretty quick to complete (once you realize what they are really asking). This diagram shows you how large they are compared to one another - it does NOT accurately indicate the distances between the Sun and each of the planets.
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
Problem 1LR
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