- Complete each system so that it has the specified number of solutions. Note: None of your equations should be identical to the given equation! a) One Solution b) No Solution y=-3x + 7 y = -3x + 7 c) Infinitely Many Solutions y = -3x + 7

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Solving Systems of Linear Equations**

1. **Complete each system so that it has the specified number of solutions.**  
   *Note: None of your equations should be identical to the given equation!*

   a) **One Solution**
   \[
   \begin{cases}
   y = -3x + 7 \\
   \underline{\hspace{3cm}}
   \end{cases}
   \]

   b) **No Solution**
   \[
   \begin{cases}
   y = -3x + 7 \\
   \underline{\hspace{3cm}}
   \end{cases}
   \]

   c) **Infinitely Many Solutions**
   \[
   \begin{cases}
   y = -3x + 7 \\
   \underline{\hspace{3cm}}
   \end{cases}
   \]
Transcribed Image Text:**Solving Systems of Linear Equations** 1. **Complete each system so that it has the specified number of solutions.** *Note: None of your equations should be identical to the given equation!* a) **One Solution** \[ \begin{cases} y = -3x + 7 \\ \underline{\hspace{3cm}} \end{cases} \] b) **No Solution** \[ \begin{cases} y = -3x + 7 \\ \underline{\hspace{3cm}} \end{cases} \] c) **Infinitely Many Solutions** \[ \begin{cases} y = -3x + 7 \\ \underline{\hspace{3cm}} \end{cases} \]
Expert Solution
Step 1: Determine the given information

The given linear equation is y equals negative 3 x plus 7.

The objective is to form a system of linear equations that has one solution, no solution, and infinitely many solutions.

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