Complete and balance the following redox reaction in acidic solution ReO, (aq) + 10 (aq) → 10, (aq) + Re(s)

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Redox reaction homework in ACIDIC solution

**Balancing Redox Reactions in Acidic Solution: An Example**

Complete and balance the following redox reaction in acidic solution:

**ReO₄⁻(aq) + IO⁻(aq) → IO₃⁻(aq) + Re(s)**

### Explanation:

In this redox reaction:
- **ReO₄⁻(aq)** (perrhenate ion) is reduced to **Re(s)** (solid rhenium).
- **IO⁻(aq)** (hypoiodite ion) is oxidized to **IO₃⁻(aq)** (iodate ion).

To balance this redox equation in acidic solution, follow these steps:

1. **Assign oxidation numbers to all elements to identify the reduction and oxidation half-reactions.**

2. **Separate the reaction into two half-reactions: one for oxidation and one for reduction.**
   
   Reduction half-reaction: ReO₄⁻(aq) → Re(s)  
   Oxidation half-reaction: IO⁻(aq) → IO₃⁻(aq)

3. **Balance the atoms in each half-reaction except for O and H.**

4. **Balance oxygen atoms by adding H₂O molecules.**

5. **Balance hydrogen atoms by adding H⁺ ions.**

6. **Balance the charges by adding electrons (e⁻).**

7. **Combine the half-reactions and ensure that the number of electrons lost in oxidation equals the number gained in reduction.**

8. **Simplify the combined reaction if necessary by removing spectators and combining like terms.**

By following these steps, you will obtain the balanced redox reaction. Always ensure that both mass and charge are balanced in the final equation.
Transcribed Image Text:**Balancing Redox Reactions in Acidic Solution: An Example** Complete and balance the following redox reaction in acidic solution: **ReO₄⁻(aq) + IO⁻(aq) → IO₃⁻(aq) + Re(s)** ### Explanation: In this redox reaction: - **ReO₄⁻(aq)** (perrhenate ion) is reduced to **Re(s)** (solid rhenium). - **IO⁻(aq)** (hypoiodite ion) is oxidized to **IO₃⁻(aq)** (iodate ion). To balance this redox equation in acidic solution, follow these steps: 1. **Assign oxidation numbers to all elements to identify the reduction and oxidation half-reactions.** 2. **Separate the reaction into two half-reactions: one for oxidation and one for reduction.** Reduction half-reaction: ReO₄⁻(aq) → Re(s) Oxidation half-reaction: IO⁻(aq) → IO₃⁻(aq) 3. **Balance the atoms in each half-reaction except for O and H.** 4. **Balance oxygen atoms by adding H₂O molecules.** 5. **Balance hydrogen atoms by adding H⁺ ions.** 6. **Balance the charges by adding electrons (e⁻).** 7. **Combine the half-reactions and ensure that the number of electrons lost in oxidation equals the number gained in reduction.** 8. **Simplify the combined reaction if necessary by removing spectators and combining like terms.** By following these steps, you will obtain the balanced redox reaction. Always ensure that both mass and charge are balanced in the final equation.
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