Compare the values obtained for the pressure(atm) of 2 mols 02 at 298.15K held in a 8.25 dm3 bulb using a) Redlick-Kwong equation: For 02: Tc = 154.6 K; Pc = 50.43 bar b) Beattie - Bridgeman equation For 02, the Beattie Bridgeman constants Ao = 0.14911 Pa m6 mol^-2 Bo = 46.24 x 10^-6 m³ mol^-1 c = 4.80 x 10^-1 m³ K3 mol-1 a = 25.62 x 10^-6 m3 mol^-1 b = 4.208 x 10^-6 m³ mol^-1 Use R= 8.314 Pa•m3/mole•k

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Show complete solution. Write the given and round everything to 4 decimal places. Note: Show the conversion and proper units if possible.

Compare the values obtained for the
pressure(atm) of 2 mols 02 at 298.15K
held in a
8.25 dm3 bulb using
a) Redlick-Kwong equation: For 02: Tc =
154.6 K; Pc = 50.43 bar
b) Beattie - Bridgeman equation
For 02, the Beattie - Bridgeman constants:
Ao = 0.14911 Pa m6 mol^-2
Bo = 46.24 x 10^-6 m³ mol^-1
c = 4.80 x 10^-1 m³ K³ mol-1
a = 25.62 x 10^-6 m³ mol^-1
b = 4.208 x 10^-6 m³ mol^-1
Use R= 8.314 Pa•m3/mole•k
Transcribed Image Text:Compare the values obtained for the pressure(atm) of 2 mols 02 at 298.15K held in a 8.25 dm3 bulb using a) Redlick-Kwong equation: For 02: Tc = 154.6 K; Pc = 50.43 bar b) Beattie - Bridgeman equation For 02, the Beattie - Bridgeman constants: Ao = 0.14911 Pa m6 mol^-2 Bo = 46.24 x 10^-6 m³ mol^-1 c = 4.80 x 10^-1 m³ K³ mol-1 a = 25.62 x 10^-6 m³ mol^-1 b = 4.208 x 10^-6 m³ mol^-1 Use R= 8.314 Pa•m3/mole•k
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