Compare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30° below -x-axis A = A cos a = 1.96 N x cos 60° = 0.98 N B,= B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A₂+ B₂+ C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N B, B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N Ry= A + By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₂ = A cos a = B₂= B cos b = R₂-A₂+ B₂ = A₂ = A sin a = B, =B sin b = R₂ = A + B₂ = R=(R₂ R₂):__ Quadrant R = √ (R₂²+R₂²) = Direction:q = tan¹ [R, /R] (c) A: 100 g along -y axis B: 200 g along -x axis Ax= A cos a = B₂B cos b = R₂-A, + B₂ = A = A sin a = B,= B sin b = R₁ = A + B₂ = R=(R R.): Quadrant R = √(R₂²+R₂²) = Direction:q=tan [R, /R.]
Compare the magnitudes of the equilibrant vectors measured from the experiment with those obtained from the graphical and component methods. Example: A: 200 g 60° above +x axis B: 300 g 45° above -x axis C: 400 g 30° below -x-axis A = A cos a = 1.96 N x cos 60° = 0.98 N B,= B cos b = 2.94 N x cos 135º = -2.08 N C, C cos g = 3.92 N x cos 210°= -3.39 N R₂-A₂+ B₂+ C₂ = -4.49 N A, A sin a = 1.96 N x sin 60° = 1.70 N B, B sin b = 2.94 N x sin 135º = 2.08 N C, C sin g = 3.92 N x sin 210° = -1.96 N Ry= A + By + Cy = 1.82 N Questions: I: (a) A: 200 g along +x axis B: 100 g 45° above -x axis A₂ = A cos a = B₂= B cos b = R₂-A₂+ B₂ = A₂ = A sin a = B, =B sin b = R₂ = A + B₂ = R=(R₂ R₂):__ Quadrant R = √ (R₂²+R₂²) = Direction:q = tan¹ [R, /R] (c) A: 100 g along -y axis B: 200 g along -x axis Ax= A cos a = B₂B cos b = R₂-A, + B₂ = A = A sin a = B,= B sin b = R₁ = A + B₂ = R=(R R.): Quadrant R = √(R₂²+R₂²) = Direction:q=tan [R, /R.]
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![II: (a) A: 150 g 60° along +y axis
B: 200 g 45° above -x axis
C: 100 g 30° below -x axis
A₂ = A cos a =
B, =B cos b =
C₁ = C cos g =
R₂-A₂+B+C₂
A, = A sin a =
B, =B sin b =
C₂ = C sin g =
R₂ = A + B + C =
R=(R₁, R₂):
R= √ (R₂²+R²) =
Quadrant
Direction:q=tan [R, R.]
1
(c) A: 200 g along +y axis
B: 100 g 60° above +x axis
C: 200 g 45° below +x axis
A₁ = A cos a =
B=B cos b =
C₁=C cos g =
R₂-A₂+B+C₂
A₁ = A sin a =
B, =B sin b =
C₁ = C sin g =
R= A + B + C₂ =
R=(R₁, R₂): _
R=√(R₂²+R₂²) =
Direction:q=tan¹ [R₂/R₂] =
Quadrant](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b319816-3828-4c3a-a4b8-8b6da6d278f2%2Fa89ae6cb-63a2-488b-9dbe-9e2e8b9acbb7%2Fkoit4l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:II: (a) A: 150 g 60° along +y axis
B: 200 g 45° above -x axis
C: 100 g 30° below -x axis
A₂ = A cos a =
B, =B cos b =
C₁ = C cos g =
R₂-A₂+B+C₂
A, = A sin a =
B, =B sin b =
C₂ = C sin g =
R₂ = A + B + C =
R=(R₁, R₂):
R= √ (R₂²+R²) =
Quadrant
Direction:q=tan [R, R.]
1
(c) A: 200 g along +y axis
B: 100 g 60° above +x axis
C: 200 g 45° below +x axis
A₁ = A cos a =
B=B cos b =
C₁=C cos g =
R₂-A₂+B+C₂
A₁ = A sin a =
B, =B sin b =
C₁ = C sin g =
R= A + B + C₂ =
R=(R₁, R₂): _
R=√(R₂²+R₂²) =
Direction:q=tan¹ [R₂/R₂] =
Quadrant
![Compare the magnitudes of the equilibrant vectors measured from the experiment with
those obtained from the graphical and component methods.
Example: A: 200 g 60° above +x axis
B: 300 g 45° above -x axis
C: 400 g 30°below -x-axis
A, A cos a = 1.96 N x cos 60° = 0.98 N
B₂B cos b = 2.94 N x cos 135º = -2.08 N
C, C cos g = 3.92 N x cos 210°= -3.39 N
R₂-A, + B + C₂ = -4.49 N
A, A sin a = 1.96 N x sin 60° = 1.70 N
By
B sin b = 2.94 N x sin 135º = 2.08 N
C, C sin g = 3.92 N x sin 210° = -1.96 N
Ry= Ay+ By + Cy = 1.82 N
Questions:
I: (a) A: 200 g along +x axis
B: 100 g 45° above -x axis
A₂ = A cos a =
B₂ =B cos b =
R₂-A₂+ B₁₂=
A₂ = A sin a =
B, = B sin b =
R₂ = A + B₂ =
R=(R₂. R₂):_ Quadrant
R = √ (R₂²+R₂²) =
Direction:q=tan [R, /R.]
(c)
A: 100 g along -y axis
B: 200 g along -x axis
A = A cos a =
B = B cos b =
R₂-A₂+ B₂ =
A = A sin a =
B, B sin b =
R=A, +B₂ =
R=(R₁, R₂): Quadrant
R = √ (R₂²+R₂²) =
Direction:q tan¹ [R, /R]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b319816-3828-4c3a-a4b8-8b6da6d278f2%2Fa89ae6cb-63a2-488b-9dbe-9e2e8b9acbb7%2F5a6jrzk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Compare the magnitudes of the equilibrant vectors measured from the experiment with
those obtained from the graphical and component methods.
Example: A: 200 g 60° above +x axis
B: 300 g 45° above -x axis
C: 400 g 30°below -x-axis
A, A cos a = 1.96 N x cos 60° = 0.98 N
B₂B cos b = 2.94 N x cos 135º = -2.08 N
C, C cos g = 3.92 N x cos 210°= -3.39 N
R₂-A, + B + C₂ = -4.49 N
A, A sin a = 1.96 N x sin 60° = 1.70 N
By
B sin b = 2.94 N x sin 135º = 2.08 N
C, C sin g = 3.92 N x sin 210° = -1.96 N
Ry= Ay+ By + Cy = 1.82 N
Questions:
I: (a) A: 200 g along +x axis
B: 100 g 45° above -x axis
A₂ = A cos a =
B₂ =B cos b =
R₂-A₂+ B₁₂=
A₂ = A sin a =
B, = B sin b =
R₂ = A + B₂ =
R=(R₂. R₂):_ Quadrant
R = √ (R₂²+R₂²) =
Direction:q=tan [R, /R.]
(c)
A: 100 g along -y axis
B: 200 g along -x axis
A = A cos a =
B = B cos b =
R₂-A₂+ B₂ =
A = A sin a =
B, B sin b =
R=A, +B₂ =
R=(R₁, R₂): Quadrant
R = √ (R₂²+R₂²) =
Direction:q tan¹ [R, /R]
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