Compare the alternatives below on the basis of their present worths using an interest rate of 14% per year compounded monthly. Maintenance and operations (M&O) costs are given. Alternative X Alternative Y

Compare the alternatives below on the basis of their present worths using an interest rate of 14% per year compounded monthly. Maintenance and operations (M&O) costs are given. Alternative X Alternative Y

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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A coal-fired plant has upgraded an emission control valve. The modification costs only $8000 and is expected to last 6 years with a $200 salvage value. The maintenance cost is expected to be high at $1700 the first year, increasing by 11% per year thereafter. Determine the present worth of the modification and maintenance cost both by hand calculation using formula and by spreadsheet at an interest rate of 8% per year.
QUESTION 8 A professional photographer who specializes in wedding-related activities paid $48,000 for equipment that will have a $2000 salvage value after 5 years. He estimates that his costs associated with each event amount to $65 per day. If he charges $350 per day for his services, how many days per year must he be employed in order to break even at an interest rate of 6% per year? The number of days required for break even, (in days per year) Round to the nearest three (3) decimal places
ChemCo Enterprises is the manufacturer of Ultra-Dry, a hydrophobic coating that will waterproofanything. Over a 5 year period, the costs associated with the pilot test product line were as follows: first cost of $43,000 and annual costs of $18,000. Annual revenue was $40,000 and used equipment was salvaged for $4,000. What rate of return did the company make on the product?
The operating cost for a machine is $40,000 for year 1 and then it increases by $5,000per year through year 10. The equivalent uniform annual cost for the machine (years 1-10) at an interest rate of 9% per year is calculated as:
Concurris Prototyping is committed to using the newest and finest equipment in its labs. Accordingly, Wilma, a senior engineer, has recommended that a 2-year-old piece of precision measurement equipment be replaced immediately. She believes it can be demonstrated that the proposed equipment is economically advantageous at a 15%-per year return and a planning horizon of 5 years. Perform the replacement analysis using the annual worth method, a 5-year study period, and the estimates below. Was Wilma correct? Equipment Original purchase price, $ Current market value, $ Remaining life, years Estimated value in 5 years, $ Salvage value after 15 years, $ AOC, $ per year Current -30,000 15,000 5 7,000 -11,000 The AW of the defender is $- challenger is $- Wilma ((Click to select)) correct. Proposed -40,000 -- 15 10,000 5,000 -3,000 and the AW of the
Equipment needed at Valero Corporation refinery for the conversion of corn stock toethanol, a cleaner burning gasoline additive, will cost $175,000 and have net cashflows of $35,000 the first year, increasing by $10,000 per year over the life of 5 years.Develop a spreadsheet chart that plots AW vs interest rate to show where (what interestrate) the project switches from financially justified to unjustified. Use AW as the verticalaxis of the chart, and interest (i) as the horizontal axis of the chart. Use a range ofinterest rates spanning from 10% to 20%, and use increments of 1%. Label both axesand use a title for the chart.
A professional mechanics who specializes in truck engines paid $46,000 for equipment that will have a $4800 salvage value after 5 years. The costs with each usage amount to $60 per day. The income is $290 per day for his services, how many days per year must he be worked in order to break even at an interest rate of 7% per year?
Calculate the annual worth of a machine that has an initial cost of $35,000, a life of 10 years, and an annual operating cost of $10,000 for the first 4 years, increasing by 1000 per year hereafter. Use an interest rate of 15% per year.
Concurris Prototyping is committed to using the newest and finest equipment in its labs. Accordingly, Wilma, a senior engineer, has recommended that a 2-year-old piece of precision measurement equipment be replaced immediately. She believes it can be demonstrated that the proposed equipment is economically advantageous at a 15%-per year return and a planning horizon of 5 years. Perform the replacement analysis using the annual worth method, a 5-year study period, and the estimates below. Was Wilma correct Equipment Current Proposed Original purchase price, $ Current market value, $ -30,000 -42,000 15,000 Remaining life, years 5 15 Estimated value in 5 years, $ 7,000 10,000 5,000 -3,000 Salvage value after 15 years, $ AOC, $ per year The AW of the defender is $- Wilma (Click to select) correct. -14,000 and the AW of the challenger is $-
1. The annual worth for years 1 through infinity of $75,000 now, $25,000 per year in years 1 through 15 and S40,000 per year in years 16 through infinity at a 10% interest per year is closest to: (a) $27,500 (b) $36,000 (c) $44,000 (d) $ 19,500 1. For the estimates in table below, calculate the equivalent annual cost of the project: First Cost, $ -950,000 Replacement Cost, year 2 AOC, $/ year Salvage value, $ -450,000 -600,000 175,000 Life, years 4 Interst Rate % 10
A project has a first cost of $200,000 with annual costs of $50,000 and revenue of $90,000 per year.What is the payback period at (a) no-return, and (b) i = 7% per year?