**Understanding Electrostatic Forces in Transparent Adhesive Tape***Common transparent adhesive tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece’s weight.*In this exercise, we explore the electrostatic principles at play when transparent adhesive tape is used. The focus is on calculating the electrostatic force necessary to support a piece of tape held above another due to the charges acquired during the dispensing process.**Problem Statement:**Assuming equal point charges as an approximation, calculate the magnitude of each charge, in coulombs, if the electrostatic force is great enough to support the weight of a 0.35 mg piece of tape held 0.85 cm above another.\[ q = \_\_\_\_\_\_\_\_\_\_ \]**Analysis:**To solve this, you'll need to apply Coulomb’s law, which describes the electrostatic force between two charges. The force can be calculated using the relation:\[ F = k \frac{|q_1 \cdot q_2|}{r^2} \]Where:- \( F \) is the electrostatic force,- \( k \) is Coulomb’s constant (\( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)),- \( q_1 \) and \( q_2 \) are the magnitudes of the charges,- \( r \) is the distance between the charges.You will also use the relation for weight (\( F_w = mg \)) to find how much force is required to support the tape, where:- \( m \) is the mass of the tape,- \( g \) is the acceleration due to gravity (\( 9.8 \, \text{m/s}^2 \)).By equating the electrostatic force needed to balance the gravitational force, you can determine the charge needed. This involves converting mass from mg to kg for consistency in SI units and solving for \( q \).No graphs or diagrams are present in this problem.

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Common transparent adhesive tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight. Assuming equal point charges as an approximation, calculate the magnitude of each charge, in coulombs, if the electrostatic force is great enough to support the weight of a 0.35 mg piece of tape held 0.85 cm above another. 9

Common transparent adhesive tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece's weight. Assuming equal point charges as an approximation, calculate the magnitude of each charge, in coulombs, if the electrostatic force is great enough to support the weight of a 0.35 mg piece of tape held 0.85 cm above another. 9

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

**Understanding Electrostatic Forces in Transparent Adhesive Tape**

*Common transparent adhesive tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsive force can be great enough to support the top piece’s weight.*

In this exercise, we explore the electrostatic principles at play when transparent adhesive tape is used. The focus is on calculating the electrostatic force necessary to support a piece of tape held above another due to the charges acquired during the dispensing process.

**Problem Statement:**

Assuming equal point charges as an approximation, calculate the magnitude of each charge, in coulombs, if the electrostatic force is great enough to support the weight of a 0.35 mg piece of tape held 0.85 cm above another.

\[ q = \_\_\_\_\_\_\_\_\_\_ \]

**Analysis:**

To solve this, you'll need to apply Coulomb’s law, which describes the electrostatic force between two charges. The force can be calculated using the relation:

\[ F = k \frac{|q_1 \cdot q_2|}{r^2} \]

Where:
- \( F \) is the electrostatic force,
- \( k \) is Coulomb’s constant (\( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)),
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
- \( r \) is the distance between the charges.

You will also use the relation for weight (\( F_w = mg \)) to find how much force is required to support the tape, where:
- \( m \) is the mass of the tape,
- \( g \) is the acceleration due to gravity (\( 9.8 \, \text{m/s}^2 \)).

By equating the electrostatic force needed to balance the gravitational force, you can determine the charge needed. This involves converting mass from mg to kg for consistency in SI units and solving for \( q \).

No graphs or diagrams are present in this problem.

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