Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2O. The molar mass of equilin is 268.34 g/mol . Find the molecular formula of the unknown compound. Express your answer as a chemical formula.
Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2O. The molar mass of equilin is 268.34 g/mol . Find the molecular formula of the unknown compound. Express your answer as a chemical formula.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produced 39.61 g CO2 and 9.01 g H2O. The molar mass of equilin is 268.34 g/mol .
Find the molecular formula of the unknown compound. Express your answer as a chemical formula.
Expert Solution
Step 1
Given : Mass of compound combusted = 13.42 g
Molar mass of compound = 268.34 g/mol.
Mass of CO2 produced = 39.61 g
And mass of water i.e H2O produced = 9.01 g
Since mass = moles X molar mass
=> 13.42 = moles of compound combusted X 268.34
=> Moles of compound combusted = 0.0500 mol.
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