Combinatorial analysis is a branch of mathematics that develops methods for performing counts efficiently. And counting problems can be present in different everyday situations, for example, in the combination of numbers in a lottery game, on license plates, among other situations. Consider a situation where a scientific researcher needs to choose three guinea pigs from a group of eight guinea pigs for an experiment. Determine the number of ways he can make the choice.
Combinatorial analysis is a branch of mathematics that develops methods for performing counts efficiently. And counting problems can be present in different everyday situations, for example, in the combination of numbers in a lottery game, on license plates, among other situations. Consider a situation where a scientific researcher needs to choose three guinea pigs from a group of eight guinea pigs for an experiment. Determine the number of ways he can make the choice.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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1. Combinatorial analysis is a branch of mathematics that develops methods for performing counts efficiently. And counting problems can be present in different everyday situations, for example, in the combination of numbers in a lottery game, on license plates, among other situations.
Consider a situation where a scientific researcher needs to choose three guinea pigs from a group of eight guinea pigs for an experiment. Determine the number of ways he can make the choice.
PS to the expert: The following image with a,b,c,d,e alternatives translated from Portuguese to English are:
Combinação = Combination
Arranjo = Arrangement
Permutação = Permutation
![O A
OB
O C
O D
OE
8!
Combinação: C8,3
-= 56
3!. (8-3)!
=-
Combinação: C8,8 ==
Arranjo: A8,3 =-
Arranjo: A8,8 =
8!
(8-3)!
8!
8!-(8-8)!
-= 336
8!
(8-8)!
=
-= 40.320
Permutação: P3 = 3·2·1= 6
1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa3a3bf59-e4d3-4b9b-a9d1-d1d67b1a736b%2F377f98cf-1068-426f-8875-59cca655b68a%2Fpgcc36_processed.png&w=3840&q=75)
Transcribed Image Text:O A
OB
O C
O D
OE
8!
Combinação: C8,3
-= 56
3!. (8-3)!
=-
Combinação: C8,8 ==
Arranjo: A8,3 =-
Arranjo: A8,8 =
8!
(8-3)!
8!
8!-(8-8)!
-= 336
8!
(8-8)!
=
-= 40.320
Permutação: P3 = 3·2·1= 6
1
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