You are interested in finding a 90% confidence interval for the average number of days of classthat college students miss each year. The data below show the number of missed days for 13randomly selected college students.11 10 8 11 8 10 11 10 10 9 4 11a. To compute the confidence interval use a ? distribution.b. With 90% confidence the population meannumber of days of class that college students miss isbetweenanddays.percent ofc. If many groups of 13 randomly selected non-residential college students are surveyed, then adifferent confidence interval would be produced from each group. Aboutthese confidence intervals will contain the true population mean number of missed class daysand aboutpercent will not contain the true population mean number of missed classdays.

Answered: college students miss each year. The…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A Las Vegas researcher is interested in finding a 90% confidence interval for the mean number of hands per hour that are dealt at Blackjack tables. The data below show the results of a study of tables 25,27,18,31,27,25,30,20,25,29,23,22,30,25 Assume a normal distribution and round your answers to two decimal places . To compute the confidence interval use the Select distribution B. With 90% confidence the population mean number of hands dealt per hour is between Select and Select hands C. groups of 14 randomly selected Blackjack tables are studied then a different confidence interval would be produced from each group About Select ] percent of these confidence intervals will contain the true population mean number of hands dealt per hour and about Select percent will not contain the true population mean number of hands dealt per hour.
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ant W 4. The percentage of CSUN freshmen who graduate from CSUN within 6 years is 55%. www.csun.edu/counts/graduation-rates.php a. Suppose that you get a random sample of 200 freshmen and construct a 95% confidence interval for the proportion of all CSUN freshmen who graduate from college within 6 years. The confidence interval is 55.8% to 60.2%. Did the confidence interval capture the parameter? You try again with a new sample. Will this interval contain the parameter? YES NO PROBABLY b. Suppose that you and 299 other statistics students each get a random sample of 200 CSUN freshmen and count the number who graduate from college within 6 years. Will all 300 of you get the same interval? YES NO ALMOST CERTAINLY NOT How many of the 300 different confidence intervals are expected to contain 55%? ALL 300 95% of 300 = 285 55% of 300 = 165 %3D %3D 5. One in three Californians is enrolled in Medi-Cal. Suppose that your class of 60 students doesn't know this. Each student gets a random sample…
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is applied to diabets Pre- diet and below. If we diet entire population after the diet, find for Mo-Ms Patient before after "mga 1 64 68 den ote 2 93 a group of 10 people with post diet weights are listed weight for the as Mo before the diet and Ms. the 95% confidence interval 95 3 2 w the mean 34 81 во 191 85 V 5 21 M 73 67 9 110 82 70 74 66 59 807278 63 81 55 HA
foullu standard deviatiðll UI Find the 99% confidence interval of the differences in IS 4.3. 24 19 23 the ages. 21. Television Watching The average number of hours of television watched per week by women over age 22 8. age 55 watch an average 55 is 48 hours. Men over age 55 watch an average of 43 hours of television per week. Random samples of 40 men and 40 women from a large retirement community yielded the following results. At the 0.01 level of significance, can it be concluded that women watch more television per week than men? Sample size Population standard Mean deviation Women an Men 40 48.2 5.6 th 40 Source: World Almanac 2012. 44.3 4.5
The data below are the ages of a random sample of 8 men in a bar. It is known that the population of ages are normally distributed with a standard deviation of 12. Determine the 93% confidence interval estimate of the population mean. 55,67,24,34,60,36,26,46 Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.
Suppose you have a sample of about 5 people where X represents cookie consumption in the past week. The following X: (6, 5, 4, 1, 1). What is the mean of X? What is the standard deviation of X? What is the standard error of X? Calculate the 95% confidence interval for X. Calculate the 99% confidence interval for X. Interpret your findings. **Hand written scratch work**
Consider the simple random sample of vehicle speeds below. Use the data to construct 3 different confidence intervals. We'll keep the sample size constant and vary the level of confidence, amd note the pattern that appears. Round results to 1 decimal place. * = 63 mph s = 10 mph n = 50 1. Construct the 80% confidence interval for vehicle speeds. 2. Construct the 90% confidence interval for vehicle speeds. 3. Construct the 99% confidence interval for vehicle speeds In 1- 2 complete sentences describe the effect increasing the level of confidence on the confidence interval.
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Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 16 38 29 2 29 28 29 Lower Limit Upper Limit
n1=16 x‾1=124 s1=35 n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 : Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.

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