Answer part a) only 2.Cold work is an important industrial technique to harden metals and alloys. Thedependence of yield strength, tensile strength and ductility on percentage of coldwork for selected metals are shown in FIGURE Q2. As an experienced MechanicalEngineer, you are to design a cylindrical rod of copper with a final diameter of 12mm, cold-worked tensile strength more than 300 MPa, yield strength of more than280 MPa and ductility of at least 15 %EL. The rod is initially 15.5 mm in diameter.а.Design the procedures involved to meet the final product specifications.Include all assumptions made, rationalization and relevant details of eachstep.b.Qualitatively describe the changes in the rod's mechanical propertiesfollowing each of the processing step in part (a). Explain the reasons in thechanges predicted. Summarise your answers using TABLE Q2. You mayexpand the table as necessary.140701209008001040 Steel601201040 Steel8007001005060070010080500600BrassBrass 803060400Brass50020Сорper4030060400Copper10 1040 SteerСоррer200300204010020010 20 30 40Percent cold work(c)10 20 30 40 50 60 7010 20 30 40 50 60 7050 60 70Percent cold workPercent cold work(a)(b)FIGURE Q2Yield strength (MPa)Yield strength (ksi)Tensile strength (MPa)Tensile strength (ksi)Ductility (%EL) TABLE Q2PropertyIncreases or decreasesDuringDuringDuringReasons for changesStep 1Step 2Step 3Yield strengthTensile strengthDuctilityHardness

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Cold work is an important industrial technique to harden metals and alloys. The dependence of yield strength, tensile strength and ductility on percentage of cold work for selected metals are shown in FIGURE Q2. As an experienced Mechanical Engineer, you are to design a cylindrical rod of copper with a final diameter of 12 mm, cold-worked tensile strength more than 300 MPa, yield strength of more than 280 MPa and ductility of at least 15 %EL. The rod is initially 15.5 mm in diameter. a. Design the procedures involved to meet the final product specifications. Include all assumptions made, rationalization and relevant details of each step.

Cold work is an important industrial technique to harden metals and alloys. The dependence of yield strength, tensile strength and ductility on percentage of cold work for selected metals are shown in FIGURE Q2. As an experienced Mechanical Engineer, you are to design a cylindrical rod of copper with a final diameter of 12 mm, cold-worked tensile strength more than 300 MPa, yield strength of more than 280 MPa and ductility of at least 15 %EL. The rod is initially 15.5 mm in diameter. a. Design the procedures involved to meet the final product specifications. Include all assumptions made, rationalization and relevant details of each step.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Question

Answer part a) only

2.
Cold work is an important industrial technique to harden metals and alloys. The
dependence of yield strength, tensile strength and ductility on percentage of cold
work for selected metals are shown in FIGURE Q2. As an experienced Mechanical
Engineer, you are to design a cylindrical rod of copper with a final diameter of 12
mm, cold-worked tensile strength more than 300 MPa, yield strength of more than
280 MPa and ductility of at least 15 %EL. The rod is initially 15.5 mm in diameter.
а.
Design the procedures involved to meet the final product specifications.
Include all assumptions made, rationalization and relevant details of each
step.
b.
Qualitatively describe the changes in the rod's mechanical properties
following each of the processing step in part (a). Explain the reasons in the
changes predicted. Summarise your answers using TABLE Q2. You may
expand the table as necessary.
140
70
120
900
800
1040 Steel
60
120
1040 Steel
800
700
100
50
600
700
100
80
500
600
Brass
Brass 80
30
60
400
Brass
500
20
Сорper
40
300
60
400
Copper
10 1040 Steer
Соррer
200
300
20
40
100
200
10 20 30 40
Percent cold work
(c)
10 20 30 40 50 60 70
10 20 30 40 50 60 70
50 60 70
Percent cold work
Percent cold work
(a)
(b)
FIGURE Q2
Yield strength (MPa)
Yield strength (ksi)
Tensile strength (MPa)
Tensile strength (ksi)
Ductility (%EL)

TABLE Q2
Property
Increases or decreases
During
During
During
Reasons for changes
Step 1
Step 2
Step 3
Yield strength
Tensile strength
Ductility
Hardness

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