Code for an algorithm to: We begin with two pointers, keeping a low and a high -> finding the midpoint and comparing it to the number we want to discover. If the goal number is greater, we move to the right because the array is sorted. If it's less than that, we shift to the left because it can't be on the right side, where all the numbers are greater than the midpoint.
Code for an algorithm to: We begin with two pointers, keeping a low and a high -> finding the midpoint and comparing it to the number we want to discover. If the goal number is greater, we move to the right because the array is sorted. If it's less than that, we shift to the left because it can't be on the right side, where all the numbers are greater than the midpoint.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Code for an
We begin with two pointers, keeping a low and a high -> finding the midpoint and comparing it to the number we want to discover. If the goal number is greater, we move to the right because the array is sorted. If it's less than that, we shift to the left because it can't be on the right side, where all the numbers are greater than the midpoint.
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