Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry- rodded coarse aggregate: Trial ( = 30.23 kg Trial 2 = 29.96 kg Trial 3 = 3(.(2 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. 6. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry- rodded coarse aggregate: Trial ( = 30.23 kg Trial 2 = 29.96 kg Trial 3 = 3(.(2 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. 6. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Coarse aggregate is placed in a rigid
bucket and rodded with a tamping
rod to determine its unit weight. The
following data are obtained:
Volume of bucket = 9.3 Liters
Mass of empty bucket = 9 kg
Mass of bucket filled with dry-
rodded coarse aggregate:
Trial ( = 30.23 kg
Trial 2 = 29.96 kg
Trial 3 = 31.(2 kg
a. Calculate the individual dry-rodded
unit weight for each trial and the
average dry-rodded unit weight of all
trials.
6. If the bulk dry specific gravity of
the aggregate is 2.65, calculate the
percent voids between aggregates
particles for each trial and the
average percent voids of all trials.
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