CNNBC recently reported that the mean annual cost of auto insurance is 1006 dollars. Assume the standard deviation is 184 dollars. You will use a simple random sample of 88 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 980.5 and 1051.1 dollars. P(980.5 < X < 1051.1) =  Part 2 Find the probability that a random sample of size n=88n=88 has a mean value between 980.5 and 1051.1 dollars. P(980.5 < M < 1051.1) =

Q: If the daily wage of a worker in a large factory has an average of 180 usd, the standard deviation…

A: Given: mean: 180 usd, standard deviation: 5 usd, n = 75.The required probability is…

Q: One prominent physician claims that 80% of those with lung cancer are chain smokers. Compute the…

A: Here, we can consider that it is Binomial distribution because  80% of people has lung cancer and…

Q: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the…

A: From the provided information,Mean (µ) = 162000Standard deviation (σ) = 36000Sample size (n) = 58

Q: CNNBC recently reported that the mean annual cost of auto insurance is $962. Assume the standard…

A: Given information: The mean annual cost of auto insurance is $962. The standard deviation is $190.…

Q: CNNBC recently reported that the mean annual cost of auto insurance is 1010 dollars. Assume the…

A: Given,mean(μ)=1010standard deviation(σ)=266sample size(n)=78

Q: In New York State, the population of teachers is known to have an average of 12.2 years of classroom…

A:

Q: A recent poll found that 59% of adults believe the state of moral values is poor. For 400 randomly…

A: Here, n = 400 and p = 0.59

Q: Scores for a standardized test are normally distributed with a mean of 1200 and a standard…

A: given data μ = 1200σ = 60 normal distributionn = 64P(1200&lt;x¯&lt;1214) = ?

Q: Tiger Woods hits an average driver 287.2 yards with a standard deviation of 24.6 yards. What is the…

A: The probability value is calculate by means of standard normal variate with the random variable,…

Q: .. Lori just bought a set of 4 tires for her car. The life of a tire is normally distributed with a…

A:

Q: Use Chebyshev's theorem to solve the problem. Find the least possible fraction of numbers in a data…

A: Consider that a random variable X has expected value μ and standard deviation, σ. Now, according to…

Q: the probability that a ball dropped from a certain height will strike the ground is 80 percent and…

A: Given: Number of trials or balls (n) = 12 Probability of success  here (p) = 0.80 Let X ~ Bin(12,…

Q: The sample of five companies in the aerospace industry was surveyed as to their return on investment…

A: We have to find sample variance s2  and sample standard deviation...

Q: Working in the garden pulling weeds/planting flowers burns an average of 200 calories per hour. If…

A: It is given that  Mean, μ = 200 Standard deviation, σ = 9 Z-Score, Z = ( X - μ )/σ

Q: The mean height of male college students in a large city is 68 inches and the standard deviation is…

A: Solution

Q: ores are normally distributed with a mean of 1518 and a standard deviation of 325. If 1 SAT score…

A: Given: μ=1518, σ=325 The corresponding z-value needed to be computed is: If 1 SAT score is randomly…

Q: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the…

A: we haven=90

Q: A random sample of 100 male students is drawn from a particular class. The mean and standard…

A:

Q: A study conducted by the Center for Population Economics at the University of Chicago studied the…

A:

Q: The population mean is 20 inches and population standard deviation is 4 inches. A random sample of…

A: mean = 20 s =4

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

Q: The average time a person spends shopping in a grocery store is 43 minutes.  If the time is normally…

A: Given:  The average time a person spends shopping in a grocery store is 43 minutes.  The time is…

Q: Energy consumption for single family comes is a mean of 1050kw and standard deviation of 218kw. Find…

A: Given information- Population mean, μ = 1050 kw Population standard deviation, σ = 218 kw We have to…

Q: The average age of UST employees is 34 years old. Assume the data is normally distributed. If the…

A: The average age of UST employees is 34 years old i.e. μ=34 The standard deviation is three years…

Q: The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A: GivenMean(μ)=6.04standard deviation(σ)=0.21Sample size(n)=33

Q: The average credit card debt for college seniors is $3262. If the debt is normally distributed with…

A: Let X be the random variable from normal distribution with mean (μ) = $3262 and standard deviation…

Q: In a recent year, grade 7 Maryland State public school students taking a mathematics assessment test…

A: In a recent year, grade 7 Maryland State public school students taking a mathematics assessment test…

Q: The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A:

Q: he manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A:

Q: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the…

A:

Q: A running back on the Spartans football team gains an average of 3.5 yards per carry with a standard…

A: Given : A running back on the Spartans football team gains an average of 3.5 yards per carry with a…

Q: s 6 hours a day. If college students were randomly selected, find the probability that the mean…

A: Let X be the random variable from normal distribution with mean (μ) = 6 hours and standard deviation…

Q: Find the probability that a single randomly selected salary that doesn't exceed 181000 dollars.…

A: The random variable X is defined as the salary for graduates which follows normal distribution with…

Q: Each year students in a local school district write a national examination. The average on this…

A: Given data Mean = 150 Standard deviation=20

Q: A large study of the heights of 550 adult men found that the mean height was 71 inches tall. The…

A: Given data  Normal distribution μ = 71σ = 7N = 550 empirical rule : approximately  68 -95- 99.7 %…

Q: Scores on the SAT test have a mean of 1518 and a standard deviation of 325. If 100 students are…

A: Scores on the SAT test have a mean of 1518 and a standard deviation of 325.

Q: find the probability that the mean time of a sample of 15 Americans who shower will be less than 12…

A: