Click the "draw structure" button to launch the drawing utility. What product is formed when the compound is treated with Benedict's reagent?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Title: Exploring Chemical Reactions with Benedict's Reagent

#### Instructions:
- Click the "draw structure" button to launch the drawing utility.
- Answer the question: What product is formed when the compound is treated with Benedict's reagent?

#### Reaction Details:
**Compound Structure:**
- The displayed compound has a chemical structure in which there is a central backbone containing four carbons (C), bearing various functional groups:
  - The first carbon (top) bears a hydroxyl group (CH2OH) and a double-bonded oxygen (O).
  - The second carbon bears a single hydrogen (H) and a hydroxyl group (OH).
  - The third carbon bears a hydroxyl group (HO) and a single hydrogen (H).
  - The fourth carbon (bottom) bears a hydroxyl group (CH2OH).

**Reacting Agent:**
- The compound reacts with Benedict's reagent, which contains \( \text{Cu}^{2+} \) ions in an alkaline medium.

**Reaction Mechanism:**
- The reaction is a classic test for reducing sugars. When the compound reacts with Benedict's reagent, the presence of the aldehyde functional group will reduce the copper ions \( \text{Cu}^{2+} \) to copper(I) oxide (Cu2O).

**Graphical Element:**
- On the right side of the compound, there is an arrow pointing towards a dashed rectangular box. Inside the box is a blue button labeled "draw structure ...".

#### Educational Insight:
When conducting such reactions, it is essential to recognize the functional groups that interact with reagents. In this case, the aldehyde group (CHO) plays a crucial role in reducing \( \text{Cu}^{2+} \) ions when using Benedict's reagent, thus forming a distinct product indicative of the presence of reducing sugars.

**Note:** Users are prompted to utilize the drawing utility to illustrate the reaction's product. This interactive step ensures that learners actively engage with the chemical transformation and understand the underlying principles of redox reactions involving carbohydrate compounds.
Transcribed Image Text:### Title: Exploring Chemical Reactions with Benedict's Reagent #### Instructions: - Click the "draw structure" button to launch the drawing utility. - Answer the question: What product is formed when the compound is treated with Benedict's reagent? #### Reaction Details: **Compound Structure:** - The displayed compound has a chemical structure in which there is a central backbone containing four carbons (C), bearing various functional groups: - The first carbon (top) bears a hydroxyl group (CH2OH) and a double-bonded oxygen (O). - The second carbon bears a single hydrogen (H) and a hydroxyl group (OH). - The third carbon bears a hydroxyl group (HO) and a single hydrogen (H). - The fourth carbon (bottom) bears a hydroxyl group (CH2OH). **Reacting Agent:** - The compound reacts with Benedict's reagent, which contains \( \text{Cu}^{2+} \) ions in an alkaline medium. **Reaction Mechanism:** - The reaction is a classic test for reducing sugars. When the compound reacts with Benedict's reagent, the presence of the aldehyde functional group will reduce the copper ions \( \text{Cu}^{2+} \) to copper(I) oxide (Cu2O). **Graphical Element:** - On the right side of the compound, there is an arrow pointing towards a dashed rectangular box. Inside the box is a blue button labeled "draw structure ...". #### Educational Insight: When conducting such reactions, it is essential to recognize the functional groups that interact with reagents. In this case, the aldehyde group (CHO) plays a crucial role in reducing \( \text{Cu}^{2+} \) ions when using Benedict's reagent, thus forming a distinct product indicative of the presence of reducing sugars. **Note:** Users are prompted to utilize the drawing utility to illustrate the reaction's product. This interactive step ensures that learners actively engage with the chemical transformation and understand the underlying principles of redox reactions involving carbohydrate compounds.
### Educational Exercise: Drawing Monosaccharides

**Instructions:**

- Click the "draw structure" button to launch the drawing utility.

**Task:**

- Consider the following monosaccharide structure provided below.

**Structure Diagram:**

```
       H
       |
       C=O
       |
      HO - C - H
       |
      HO - C - H
       |
      HO - C - H
       |
       C - OH
       |
     HO - C - H
       |
     CH2OH
```

This diagram represents a linear form of a monosaccharide.

**Activity:**

- Draw the α anomer of the cyclic form of the given monosaccharide.

**Tool:**

- To assist you, use the drawing tool available by clicking the "draw structure" button below.

[draw structure ...]

### Detailed Explanation:

**Diagram Details:**

- The diagram shows a linear form of a sugar molecule (a monosaccharide), indicating the specific arrangement of hydroxyl groups (-OH) and hydrogen atoms (H) attached to the carbon backbone.
- At the top of the diagram, the C=O group denotes the carbonyl group.
- Hydroxyl groups (OH) are shown attached to carbons at varying positions, indicating the orientation of these groups in the linear chain.
- At the bottom, a CH2OH group is attached to the last carbon in the chain, characteristic of a sugar.

In the cyclic form, the molecule will form a ring structure where the hydroxyl group on one end (typically the fifth carbon in the chain) reacts with the carbonyl group to create a ring. The α anomer refers to the specific orientation of the hydroxyl group attached to the anomeric carbon (the new chiral center formed during ring closure), typically in the opposite direction to the CH2OH group.
Transcribed Image Text:### Educational Exercise: Drawing Monosaccharides **Instructions:** - Click the "draw structure" button to launch the drawing utility. **Task:** - Consider the following monosaccharide structure provided below. **Structure Diagram:** ``` H | C=O | HO - C - H | HO - C - H | HO - C - H | C - OH | HO - C - H | CH2OH ``` This diagram represents a linear form of a monosaccharide. **Activity:** - Draw the α anomer of the cyclic form of the given monosaccharide. **Tool:** - To assist you, use the drawing tool available by clicking the "draw structure" button below. [draw structure ...] ### Detailed Explanation: **Diagram Details:** - The diagram shows a linear form of a sugar molecule (a monosaccharide), indicating the specific arrangement of hydroxyl groups (-OH) and hydrogen atoms (H) attached to the carbon backbone. - At the top of the diagram, the C=O group denotes the carbonyl group. - Hydroxyl groups (OH) are shown attached to carbons at varying positions, indicating the orientation of these groups in the linear chain. - At the bottom, a CH2OH group is attached to the last carbon in the chain, characteristic of a sugar. In the cyclic form, the molecule will form a ring structure where the hydroxyl group on one end (typically the fifth carbon in the chain) reacts with the carbonyl group to create a ring. The α anomer refers to the specific orientation of the hydroxyl group attached to the anomeric carbon (the new chiral center formed during ring closure), typically in the opposite direction to the CH2OH group.
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