Click the "draw structure" button to launch the drawing utility. Draw the product formed when the Lewis acid (CH3CH₂) 3C reacts with the Lewis base H₂O. I H3CH₂- CH₂CH3 + OH₂ CH₂CH3 edit structure ...

Question 17 Give the starting material. (a) (b) O O O a C d (c) (d) A Moving to another question will save this response. 1. Hg(OAc)2, H₂O 2. NaBH4 OH

Explain why the pH of a 0.25 M solution of formic acid (HCO2H) has a lower pH than a solution that is 0.25 M in both formic acid and sodium formate (NaCO2H). Please include chemical reactions.

Treating choline with acetic anhydride gives acetylcholine, a neurotransmitter. Write an equation for the formation of acetylcholine. (CH,),NCH,CH,OH Choline

Write an equation showing NH3 reacting as an acid with CH3O- and an equation showing it reacting as a base with HBr.

Do not give handwriting solution.

Complete the reaction.

HCl (excess) H₂O₂

a) The F-F bond dissociation energy (BDE) is approximately 37 kcal/mol.For reference, a “normal” C-C or C-H bond has a BDE of approximately 100kcal/mol. Briefly explain why the F-F bond is much weaker than a C-C or C-H bond b) Consider the balanced equation below, where “Ph” indicates amonosubstituted benzene (“phenyl”) ring: Ph-H + F-F -> Ph-F + H-F The BDEs of the molecules involved, in kcal/mol, are as follows:Bond      BDE (kcal/mol)Ph-H      112Ph-F      116H-F      136 What is the delta H for the fluorination of benzene by F2? Is the reaction favored or not? c) Why is the fluorination of benzene with F2 rarely done? For reference, thebromination of benzene with Br2 has a delta H of approximately -12 kcal/mol.

The amount of tartaric acid is responsible for the tartness of wine and controls the acidity of the wine.  Tartaric acid also plays a very significant role in the overall taste, feel and color of a wine.   Tartaric acid is a diprotic organic acid The chemical formula for tartaric acid is C4H6O6 and its structural formula is HO2CCH(OH)CH(OH)CO2H.   A 50.00 mL sample of a white dinner wine required 21.48 mL of 0.03776 M NaOH to achieve a faint pink color.  Express the acidity of the wine in terms of grams of tartaric acid, H2C4H4O6 (M. M.  =  150.10) per 100 mL of wine.  Assume that the two acidic hydrogens are titrated at the end point. MM H2C4H4O6 = 150.10 MM NaOH = 40.00 Below is the balanced chemical equation for this titration.