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Click in the answer box to activate the pal Give the formula of the conjugate base of HCO- 3

Click in the answer box to activate the pal Give the formula of the conjugate base of HCO- 3

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Instructions:** *Click in the answer box to activate the palette.* **Question:** *Give the formula of the conjugate base of \( H_2CO_3 \).* **Answer Box:** \( HCO_3^- \) **Explanation:** This exercise is asking you to identify the conjugate base of carbonic acid (\( H_2CO_3 \)). When carbonic acid (\( H_2CO_3 \)) loses a proton (\( H^+ \)), it forms its conjugate base, bicarbonate (\( HCO_3^- \)). ### Understanding Conjugate Bases 1. **Definition:** A conjugate base is what remains after an acid has donated a proton during a chemical reaction. 2. **Example:** For carbonic acid (\( H_2CO_3 \)): - **Acid:** \( H_2CO_3 \) - **Donates a proton (\( H^+ \)):** - **Conjugate Base:** \( HCO_3^- \) This principle is illustrated in the given question. Ensure you properly use the chemical notation palette provided when entering your answers.
Transcribed Image Text:**Instructions:** *Click in the answer box to activate the palette.* **Question:** *Give the formula of the conjugate base of \( H_2CO_3 \).* **Answer Box:** \( HCO_3^- \) **Explanation:** This exercise is asking you to identify the conjugate base of carbonic acid (\( H_2CO_3 \)). When carbonic acid (\( H_2CO_3 \)) loses a proton (\( H^+ \)), it forms its conjugate base, bicarbonate (\( HCO_3^- \)). ### Understanding Conjugate Bases 1. **Definition:** A conjugate base is what remains after an acid has donated a proton during a chemical reaction. 2. **Example:** For carbonic acid (\( H_2CO_3 \)): - **Acid:** \( H_2CO_3 \) - **Donates a proton (\( H^+ \)):** - **Conjugate Base:** \( HCO_3^- \) This principle is illustrated in the given question. Ensure you properly use the chemical notation palette provided when entering your answers.
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