Clearly indicate with reasons the types of random variable the expression “Heights of people in inch” and “Heights of people to the nearest inch.” Nuclear power plants have redundant components in important systems to reduce the chance of catastrophic failure. Assume that a plant has two gauges to measure the level of coolant in the reactor core and that each gauge has probability 0.01 of failing. Assume that one potential cause of gauge failure is that the electric cables leading from the core to the control room where the gauge are located may burn up in a fire. Someone wishes to estimate the probability that both gauges fail, and makes the following calculation:  c) Is the probability of  likely to be too high or too low? Explain.

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Question 5

a) Clearly indicate with reasons the types of random variable the expression “Heights of people in inch” and “Heights of people to the nearest inch.”

Nuclear power plants have redundant components in important systems to reduce the chance of catastrophic failure. Assume that a plant has two gauges to measure the level of coolant in the reactor core and that each gauge has probability 0.01 of failing. Assume that one potential cause of gauge failure is that the electric cables leading from the core to the control room where the gauge are located may burn up in a fire. Someone wishes to estimate the probability that both gauges fail, and makes the following calculation: 

c) Is the probability of  likely to be too high or too low? Explain.

located may burn up in a fire. Someone wishes to estimate the
probability that both gauges fail, and makes the following
calculation:
P(both gauges fail) = P(first gauge fails) x P(second gauge fails)
= (0.01)(0.01)
= 0.0001
Use the above preamble to answer questions 5b to 5c.
b) Explain why this assumption is probably not justified in the present
case.
Transcribed Image Text:located may burn up in a fire. Someone wishes to estimate the probability that both gauges fail, and makes the following calculation: P(both gauges fail) = P(first gauge fails) x P(second gauge fails) = (0.01)(0.01) = 0.0001 Use the above preamble to answer questions 5b to 5c. b) Explain why this assumption is probably not justified in the present case.
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