Classroom Example Using 0.46 as a coefficient of friction, determine how fast a car EXAMPLE 6 Apply Your Skill was traveling if it skidded 275 feet. Using 0.35 as a coefficient of friction, determine how fast a car was traveling if it skidded 325 feet. Solution Substitute 0.35 for f and 325 for D in the formula. S = V30Df = V 30(325)(0.35) = 58 to the nearest whole number The car was traveling at approximately 58 miles per hour. The period of a pendulum is the time it takes to swing from one side to the other side and back. The formula L T = 27 32 where T represents the time in seconds and L the length in feet, can be used to determine the period of a pendulum (see Figure 5.1). Figure 5.1
Classroom Example Using 0.46 as a coefficient of friction, determine how fast a car EXAMPLE 6 Apply Your Skill was traveling if it skidded 275 feet. Using 0.35 as a coefficient of friction, determine how fast a car was traveling if it skidded 325 feet. Solution Substitute 0.35 for f and 325 for D in the formula. S = V30Df = V 30(325)(0.35) = 58 to the nearest whole number The car was traveling at approximately 58 miles per hour. The period of a pendulum is the time it takes to swing from one side to the other side and back. The formula L T = 27 32 where T represents the time in seconds and L the length in feet, can be used to determine the period of a pendulum (see Figure 5.1). Figure 5.1
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
use radicals to solve the problems. Use a coefficient of friction of 0.4 in the formula from Example 6 and find the speeds of cars that left skid marks of lengths 150 feet, 200 feet, and 350 feet. Express your answers to the nearest mile per hour.
![Classroom Example
Using 0.46 as a coefficient of
friction, determine how fast a car
EXAMPLE 6
Apply Your Skill
was traveling if it skidded 275 feet.
Using 0.35 as a coefficient of friction, determine how fast a car was traveling if it skidded
325 feet.
Solution
Substitute 0.35 for f and 325 for D in the formula.
S = V30Df = V 30(325)(0.35) = 58
to the nearest whole number
The car was traveling at approximately 58 miles per hour.
The period of a pendulum is the time it takes to swing from one side to the other side
and back. The formula
L
T = 27
32
where T represents the time in seconds and L the length in feet, can be used to determine the
period of a pendulum (see Figure 5.1).
Figure 5.1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Facef5bde-107f-46a9-bb7b-d102dac67e52%2F49a2d9ce-7190-4a21-8ebc-49ad5ff17a98%2Fqr3utmd_processed.png&w=3840&q=75)
Transcribed Image Text:Classroom Example
Using 0.46 as a coefficient of
friction, determine how fast a car
EXAMPLE 6
Apply Your Skill
was traveling if it skidded 275 feet.
Using 0.35 as a coefficient of friction, determine how fast a car was traveling if it skidded
325 feet.
Solution
Substitute 0.35 for f and 325 for D in the formula.
S = V30Df = V 30(325)(0.35) = 58
to the nearest whole number
The car was traveling at approximately 58 miles per hour.
The period of a pendulum is the time it takes to swing from one side to the other side
and back. The formula
L
T = 27
32
where T represents the time in seconds and L the length in feet, can be used to determine the
period of a pendulum (see Figure 5.1).
Figure 5.1
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