Class Management | HelpHW-9 Begin Date: 4/19/2021 12:01:00 AMDue Date: 4/27/2021 11:00:00 PM End Date: 4/27/2021 11:00:00 PM(10%) Problem 9: An inductor has N= 990 turns. When the current going through it is I= 0.36 A, themagnetic flux through one coil is = 1.2 × 10-0 T•m². The current is then changed to I, = 1.62 A in At =6.5 s.Randomized VariablesN= 990I = 0.36 AD = 1.2 x 10-6 T:m?I = 1.62 AAt = 6.5sOtheexpertta.comE V 25% Part (a) Express the inductance L in terms ofN, I and .L=N OI/ Correct!8 25% Part (b) Calculate the numerical value of L in H.L = 2166.6L = 2167X Attempts RemainD 8 25% Part (c) Express the magnitude of the induced emf in terms of L, I, 1 , and At.Grade SummaryLI1/At|Deductions3%Potential97%aΔt7НОМЕSubmissionsAttempts remaining: 4(30% per attempt)detailed viewФ5d.g13IIL+END39%Vol BACKSPACECLEARnDELSubmitFeedbackI give up!HintHints: 0% deduction per hint. Hints remaining: 1Feedback: 0% deduction per feedback.E A 25% Part (d) Calculate the numerical value of ɛ in V.All content e 2021 Fman TA ULO

Given: The number of turns is 990. The initial current flowing is 0.36 A. The magnetic flux is…

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