CIVIL ENGINEERING -REINFORCED CONCRETE DESIGN Problem#2: Determine the permissible ultimate moment capacity of the beam shown in figure. fc'= 27.5 MPa, fy = 345 MPa. 350 mm As = 775mm² As =3625 mm² 63 mm 600 mm Questions: How they get the valme = below: 96₁ 4₁ 3042-4 and 2 answers 121-12mm. Please how you get that answer and show your formula the greev of to arrive
CIVIL ENGINEERING -REINFORCED CONCRETE DESIGN Problem#2: Determine the permissible ultimate moment capacity of the beam shown in figure. fc'= 27.5 MPa, fy = 345 MPa. 350 mm As = 775mm² As =3625 mm² 63 mm 600 mm Questions: How they get the valme = below: 96₁ 4₁ 3042-4 and 2 answers 121-12mm. Please how you get that answer and show your formula the greev of to arrive
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![CIVIL ENGINEERING -REINFORCED
Problem#2:
Determine the permissible ultimate moment capacity of
the beam shown in figure. fc'= 27.5 MPa, fy = 345 MPa.
350 mm
As' = 775mm²
O
O
As =3625 mm2
O
O
f
Questions:
the green
How they get the value of
circle below: 96, 4, 3042-4 and 2 to arrive
121-12 mm.
Please how
answers
that answer
you get
and show your formula.
Solution to #2
As, As - As'=3625-775 = 2850 mm ²
Afy
2850(345)
0.85 fc'b 0.85(27.5)350
a=
a
63 mm
600(a−ß,d')_600(120.18-[0.85(63)])
a = B₁c
129.12=0.85c
c=14249mm
600 mm
a=
Compression steel does not yields at failure
[Fx=0
0.85fc'ab + A, 'fs' = Afy
0.85(27.5)350a + 775fs' = 3625(345)
10.56a+fs'= 1613.7
с
120.18
d-c
96+√(96)² + 4(30426)
2
= 120.18mm
fs'=1613.7-10.56 a
f=334.7 MPa<fy
600(121.12-53.55)
121.12
0.003
CONCRETE DESIGN
=332.65MPa< fy
& (strain of steel)
-=121.12mm
d-c
EQ.1
C
0.003
187.18
E₁
600-187.18
&₁ = 0.0088 <0.005
This is a tension-controlled section](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd26af165-a48a-4025-869b-89b03c48d51c%2Fad5ed82f-4b9d-4f8b-ba7e-662157c1d85e%2Fro4fpq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:CIVIL ENGINEERING -REINFORCED
Problem#2:
Determine the permissible ultimate moment capacity of
the beam shown in figure. fc'= 27.5 MPa, fy = 345 MPa.
350 mm
As' = 775mm²
O
O
As =3625 mm2
O
O
f
Questions:
the green
How they get the value of
circle below: 96, 4, 3042-4 and 2 to arrive
121-12 mm.
Please how
answers
that answer
you get
and show your formula.
Solution to #2
As, As - As'=3625-775 = 2850 mm ²
Afy
2850(345)
0.85 fc'b 0.85(27.5)350
a=
a
63 mm
600(a−ß,d')_600(120.18-[0.85(63)])
a = B₁c
129.12=0.85c
c=14249mm
600 mm
a=
Compression steel does not yields at failure
[Fx=0
0.85fc'ab + A, 'fs' = Afy
0.85(27.5)350a + 775fs' = 3625(345)
10.56a+fs'= 1613.7
с
120.18
d-c
96+√(96)² + 4(30426)
2
= 120.18mm
fs'=1613.7-10.56 a
f=334.7 MPa<fy
600(121.12-53.55)
121.12
0.003
CONCRETE DESIGN
=332.65MPa< fy
& (strain of steel)
-=121.12mm
d-c
EQ.1
C
0.003
187.18
E₁
600-187.18
&₁ = 0.0088 <0.005
This is a tension-controlled section
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