Properties of the Wide Flange Section: gy ty = 61 mm d = 1,050 mm Igx = 14.734 x10° mm* Igy = 715.918 x10 mm* x6 2a. Determine the location of the centroid of the built-up section measured from the top. 2b. Determine the moment of inertia of the built-up section with respect to the horizontal axis of its centroid. (Hint: Use the concept of transfer of moment of inertia.) Problem#2: (Built-up section using channel and wide flange section) Properties of the Channel Section: Ew = 8mm x = 12.67mm !gx = 6.327 x10“ mm* Wide Flange (next page) gx 'gy = 0. 362 x10“ mm*

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Corrections A(channel)=9,400mm² A(wide-flange)=62,200mm²
Properties of the Wide Flange Section:
gy
ty = 61 mm
d = 1,050 mm
Igx = 14.734 x10° mm*
Igy = 715.918 x10 mm*
x6
2a. Determine the location of the centroid of the built-up section measured from the top.
2b. Determine the moment of inertia of the built-up section with respect to the horizontal
axis of its centroid. (Hint: Use the concept of transfer of moment of inertia.)
Transcribed Image Text:Properties of the Wide Flange Section: gy ty = 61 mm d = 1,050 mm Igx = 14.734 x10° mm* Igy = 715.918 x10 mm* x6 2a. Determine the location of the centroid of the built-up section measured from the top. 2b. Determine the moment of inertia of the built-up section with respect to the horizontal axis of its centroid. (Hint: Use the concept of transfer of moment of inertia.)
Problem#2: (Built-up section using channel and wide flange section)
Properties of the Channel Section:
Ew = 8mm
x = 12.67mm
!gx = 6.327 x10“ mm*
Wide Flange (next page)
gx
'gy = 0. 362 x10“ mm*
Transcribed Image Text:Problem#2: (Built-up section using channel and wide flange section) Properties of the Channel Section: Ew = 8mm x = 12.67mm !gx = 6.327 x10“ mm* Wide Flange (next page) gx 'gy = 0. 362 x10“ mm*
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Step 1

Answer 

(2a) Calculation of location of the centroid of built up section from top

To calculate the centroid of given built up section from top we have y = Ac*yc+Awf*ywfAc+Awf

Civil Engineering homework question answer, step 1, image 1

Ac = Area of channel section

Ac = 9400 mm2 

Awf= Area of wide flange section

Awf= 62200 mm2 

yc = Centroid of channel section from top

yc = x = 12.67 mm

 ywf = Centroid of wide flange section from top

ywf = twd2

ywf = 8 + 10502

ywf = 533 mm

Substitute the values to get 'y'

y = Ac*yc+Awf*ywfAc+Awf

y = 9400*12.67+62200*5339400+62200

y = 464.69 mm

" Location of the centroid of built up section from top = 464.69 mm "

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