USE NATIONAL STRUCTURAL CODE OF THE PHILIPPINES 2015 From the given figure determine the safe value of W in KN/m for LRFD and ASD design, base on thegiven design connection. Neglect the self-weight of the truss and other component. The connection at gridA is pinned and roller for grid B. Assume that all the joints were pinned connection. Disregard the filletedges of the 50 x 50 x 6mm angle bar. (Note: The bolts coincide along the centroid of the given two angleconnection)Both the gusset plates and angles are A36 Steel.Fnv=165MpaDeformation at the bolt hole at service load is a design consideration.AB875775800800525800B00AC07751ämm THK. GUSSET PLATE3-18m A7 HEX BOLTw WASHER24 - 50 1 50 x Grm THK. ANGLE BARTRUSS MEMBER W PRMER PAINT FINISH

Answered: From the given figure determine the…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

USE NATIONAL STRUCTURAL CODE OF THE PHILIPPINES 2015

From the given figure determine the safe value of W in KN/m for LRFD and ASD design, base on the
given design connection. Neglect the self-weight of the truss and other component. The connection at grid
A is pinned and roller for grid B. Assume that all the joints were pinned connection. Disregard the fillet
edges of the 50 x 50 x 6mm angle bar. (Note: The bolts coincide along the centroid of the given two angle
connection)
Both the gusset plates and angles are A36 Steel.
Fnv=165Mpa
Deformation at the bolt hole at service load is a design consideration.
A
B
875
775
800
800
525
800
B00
AC0
775
1ämm THK. GUSSET PLATE
3-18m A7 HEX BOLT
w WASHER
24 - 50 1 50 x Grm THK. ANGLE BAR
TRUSS MEMBER W PRMER PAINT FINISH

Expert Solution

Step 1

$G i v e n t h a t - T o d e t e r m i n e t h e n e t a r e a f o r t h e p l a t e s h o w n i n f i g u r e .$

$(a) A_{g} = 2400 \times 14 = 3360 m m^{2} (1) — (1) s e c t i o n A_{n e t} = (240 - 4 (23.5) + 2 (\frac{50}{4 \times 50}) \times 14) = 2394 m m^{2} (1) - (2) s e c t i o n A_{n e t} = (240 - 3 \times 23.5 + \frac{50^{2}}{4 \times 50}) \times 14 = 2543 m m^{2} (1) - (3) s e c t i o n A_{n e t} = [240 - 4 \times 23.5 + \frac{2 \times 50^{2}}{4 \times 50}] 14 = 2394 m m^{2} T h e r e f o r e, T h e s m a l l e s t o f t h e s e c t i o n i s A_{n e t} = 2394 m m^{2}$

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Recommended textbooks for you

Structural Analysis

Civil Engineering

ISBN:

9781337630931

Author:

KASSIMALI, Aslam.

Publisher:

Cengage,