City Median Household Income ($) City Median Household Income ($) Pelham, AL 66,772 Bozeman, MT 49,303 Juneau, AK 84,101 Papillion, NE 79,131 Paradise Valley, AZ 138,192 Sparks, NV 54,230 Fayetteville, AR 40,835 Nashua, NH 66,872 Monterey Park, CA 57,419 North Arlington, NJ 73,885 Lone Tree, CO 116,761 Rio Rancho, NM 58,982 Manchester, CT 64,828 Valley Stream, NY 88,693 Hockessin, DE 115,124 Concord, NC 54,579 St. Augustine, FL 47,748 Dickinson, ND 71,866 Vinings, GA 73,103 Wooster, OH 43,054 Kapaa, HI 62,546 Mustang, OK 66,714 Meridian, ID 62,899 Beaverton, OR 58,785 Schaumburg, IL 73,824 Lower Merion, PA 117,438 Fishers, IN 87,043 Warwick, RI 63,414 Council Bluffs, IA 46,844 Mauldin, SC 57,480 Lenexa, KS 76,505 Rapid City, SD 47,788 Georgetown, KY 58,709 Franklin, TN 82,334 Bossier City, LA 47,051 Allen, TX 104,524 South Portland, ME 56,472 Orem, UT 54,515 Rockville, MD 100,158 Colchester, VT 69,181 Waltham, MA 75,106 Reston, VA 112,722 Farmington Hills, MI 71,154 Mercer Island, WA 128,484 Woodbury, MN 99,657 Morgantown, WV 38,060 Olive Branch, MS 62,958 New Berlin, WI 74,983 St. Peters, MO 57,728 Cheyenne, WY 56,593 (a) Compute the mean and median (in $) for these household income data. mean$median$ (b) Compare the mean and median values for these data. What does this indicate about the distribution of household income data? The mean household income is  ---Select--- smaller than larger than the same as the median household income. This indicates that the distribution of household income is  ---Select--- positively skewed (skewed right). negatively skewed (skewed left). symmetric. (c) Compute the range and standard deviation (in $) for these household income data. (Round your standard deviation to the nearest cent.) range$standard deviation$

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Each year Money magazine publishes a list of "Best Places to Live in the United States." These listings are based on affordability, educational performance, convenience, safety, and livability. The list below shows the median household income of Money magazine's top city in each U.S. state for 2017.†
City Median Household
Income ($)
City Median Household
Income ($)
Pelham, AL 66,772 Bozeman, MT 49,303
Juneau, AK 84,101 Papillion, NE 79,131
Paradise Valley, AZ 138,192 Sparks, NV 54,230
Fayetteville, AR 40,835 Nashua, NH 66,872
Monterey Park, CA 57,419 North Arlington, NJ 73,885
Lone Tree, CO 116,761 Rio Rancho, NM 58,982
Manchester, CT 64,828 Valley Stream, NY 88,693
Hockessin, DE 115,124 Concord, NC 54,579
St. Augustine, FL 47,748 Dickinson, ND 71,866
Vinings, GA 73,103 Wooster, OH 43,054
Kapaa, HI 62,546 Mustang, OK 66,714
Meridian, ID 62,899 Beaverton, OR 58,785
Schaumburg, IL 73,824 Lower Merion, PA 117,438
Fishers, IN 87,043 Warwick, RI 63,414
Council Bluffs, IA 46,844 Mauldin, SC 57,480
Lenexa, KS 76,505 Rapid City, SD 47,788
Georgetown, KY 58,709 Franklin, TN 82,334
Bossier City, LA 47,051 Allen, TX 104,524
South Portland, ME 56,472 Orem, UT 54,515
Rockville, MD 100,158 Colchester, VT 69,181
Waltham, MA 75,106 Reston, VA 112,722
Farmington Hills, MI 71,154 Mercer Island, WA 128,484
Woodbury, MN 99,657 Morgantown, WV 38,060
Olive Branch, MS 62,958 New Berlin, WI 74,983
St. Peters, MO 57,728 Cheyenne, WY 56,593
(a)
Compute the mean and median (in $) for these household income data.
mean$median$
(b)
Compare the mean and median values for these data. What does this indicate about the distribution of household income data?
The mean household income is  ---Select--- smaller than larger than the same as the median household income. This indicates that the distribution of household income is  ---Select--- positively skewed (skewed right). negatively skewed (skewed left). symmetric.
(c)
Compute the range and standard deviation (in $) for these household income data. (Round your standard deviation to the nearest cent.)
range$standard deviation$
(d)
Compute the first and third quartiles (in $) for these household income data.
Q1$Q3$
(e)
Are there any outliers in these data?
There  ---Select--- are 0 values is 1 value are 2 values are 3 values are 4 values below the lower limit and  ---Select--- 0 values 1 value 2 values 3 values 4 values above the upper limit.
What does this suggest about the data?
There are no outliers in the data, which is likely why the mean value is greater than the median.There are no outliers in the data, which is likely why the mean value is less than the median.    There are no outliers in the data, which is likely why the mean value is the same as the median.There are outliers in the data, which is likely why the mean value is greater than the median.There are outliers in the data, which is likely why the mean value is less than the median.
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