None Citric acid is triprotic (H3Cit), with acidity constants pKa1 = 3.13, pKa2 = 4.76, and pKa3=6.40. (a) Writeout the expressions for 0, 1, 2, and 3 as a function ofthe Ka values and()H+. (b) Identify the region whereeach citrate species is dominant. (c) Draw a log C - pHdiagram for a solution with 101 M TOTCit over the pHrange1.0

(a) Expressions for 0, 1, 2, and 3 as a function of Ka values and [H+]:Citric acid (H₃Cit) is…

Answered: Citric acid is triprotic (H3Cit), with…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Given the following data NH3(g) → > N₂(g) + ³H₂(g) 2H₂(g) + O₂(g) →→ 2H₂O(g) calculate AH for the reaction ΔΗ = 46 kJ ΔΗ = -484 kJ 2N₂(g) + 6H₂O(g) →→30₂(g) + 4NH3(g)
Research studies have found that the price elasticity of demand for bread is equal to -0.40 and the price elasticity of demand of butter is equal to -1.13. Holding everything else constant, if the price of bread and the price of butter each increase by 10 percent: (a) Will the revenue from sales of bread increase or decrease? (b) Will the revenue from sales of butter increase or decrease?
Use and modify some/all the reactions provided to form the indicated overall reaction according to Hess' Law. • If a reaction is not used in your Hess' Law process, include that indication by multiplying the reaction by "0" • If no modification is needed and the reaction is applied as written below, include that indication by multiplying the reaction by "1" • Use whole numbers and simple fractions (such as "2" or "1/2", not 0.5) and negative signs (such as "-2") where needed Then calculate and report the enthalpy change (in kJ) for the overall reaction in the indicated blank, including units with your written value and rounded to 1 decimal place. Overall Reaction: CS2(1) + 302(g) → CO2(g) + 2SO2(g) Rxn # Reaction ΔΗ° (kJ) 1 C(s) → C(g) 716.67 2 C(s) + O2(g) → CO2(g) -393.5 3 3Fe(s) +202(g) → Fe3O4(s) -1118 4 C(s) + 2S(s) → CS2(1) 87.9 5 CH4(g) + O2(g) → CO₂(g) + H₂O(g) -882.0 6 S(s) + O2(g) → SO2(g) -296.8 N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(g) -629.1 7
complete the following reaction
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(4d-202) A buffer solution is made by mixing H3PO4 and NaH2PO4 in water. How does this buffer system neutralize an addition of 5 mL of 0.45 M NaOH? Choose one of the options below. • The H3PO4, as a weak acid, will neutralize the added NaOH • The NaH2PO4, as a weak base, will neutralize the added NaOH • The H3PO4, as a weak base, will neutralize the added NaOH • The NaH2PO4, as a weak acid, will neutralize the added NaOH For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). Paragraph Arial 14px A v Ix Q x² X, g ST 田用国 EXE ABC Ť {;} +) P. O WORDS POWERED BY TINY +]
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ORT SHEET Heat of Neutralization EXPERIMENT elemsboomfchg lom 12 A. Heat Capacity of Calorimeter 1. Temp. of calorimeter and water before mixing 2. Temp. of warm water °C 22.0 39,0 30.3 3. Maximum temp. determined from your curve °C 4. Heat lost by warm water (temp decrease x °C 50.0 g x 4.184 J/K-g) = 02), 5. Heat gained by cooler water (temp. increase x 50.0 g x 4.184 J/K-g) = 30,3 22.0)x 13626J s0.0gmpi S0.0gy 6. Heat gained by the calorimeter [(4) – (5)] = 7. Heat capacity of calorimeter: heat gained by the calorimeter temperature increase J/K 3. Heat of Neutralization of HCl-NaOH 22.2 22.2. °C . Temp. of calorimeter and NaOH Temp. of HCI AT determined from your curve after adding HC1 °C to the NaOH Heat gained by solution (temperature increase x ON 100 g x 4.184 J/K-g) = 9977.8J %3D Heat gained by calorimeter (temperature increase x heat capacity of calorimeter) = J %3D Total joules released by reaction [(3) + (4)] = Tight O 2018 Pearson Education, Inc.
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