Circuits I Lab 3 Pre-Lab Instructions Part 1: Solve for the voltages and currents for this circuit using and calculations. Place answers in the tables, find percent error where indicated, and submit your completed document. V1 KCL: i, = i₂+ iz Ohm's Law J=iR 0 ₁=i₁* R₁ √2 = 1₂ * R₂ Hilt √3 = 13* R3 √4=13* R4 √5=13* R5 VS 5V R1 m 1kQ R6 h h V2 e www 3.3kQ V6 Kirchhoff's Voltage Law KVL Loop 1 (Nodes a b e f a): KVL Loop 2 (Nodes b c d e b): Kirchhoff's Current Law h b R2 2.2kQ V3 R3 2.2kQ R5 www 1kQ V5 V4 d R4 1kQ

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Circuits 1 Pre Lab 2
Circuits I Lab 3 Pre-Lab Instructions
Part 1: Solve for the voltages and currents for this circuit using
hand calculations. Place answers in the tables, find percent error
where indicated, and submit your completed document.
VS
5V
V₁ = i₁* R₁
V₂ = 1₂ * R₂
V3 = 13* R3
V4 =13* R4
V5=13* R5
V6 = i₁* R6
V1
h
R1
ww
1kQ h
R6
www
3.3kQ
V6
V2
e
R2
2.2kQ
Kirchhoff's Voltage Law
KVL Loop 1 (Nodes a b e fa):
KVL Loop 2 (Nodes b c d e b):
Kirchhoff's Current Law
KCL: i, = i₂+ iz
Ohm's Law
V=iR
V3
R3
2.2kQ
R5
1kQ
V5
V4
d
R4
1kQ
Substitute resistor values into Ohm's Law formulas. Put those
values into KVL equations. Example: V₁ = i₁* R₁ V₁ = i₁* 1
V₁ = i₁
Just realize that since the resistors in this circuit are in KQ, then
current will be in μA.
Using the two KVL equations and the KCL equation, use
substitution and you will have 3 equations and 3 unknowns, i,
i2, and i3. Solve for all three currents. Then plug the currents
into each Ohm's Law equation to solve for all six voltages.
Finally, verify the KVL equations by plugging in the voltages.
Part 2: Solve for the voltage drops across the 330 resistor or
resistor series and place the answers in the table.
Transcribed Image Text:Circuits I Lab 3 Pre-Lab Instructions Part 1: Solve for the voltages and currents for this circuit using hand calculations. Place answers in the tables, find percent error where indicated, and submit your completed document. VS 5V V₁ = i₁* R₁ V₂ = 1₂ * R₂ V3 = 13* R3 V4 =13* R4 V5=13* R5 V6 = i₁* R6 V1 h R1 ww 1kQ h R6 www 3.3kQ V6 V2 e R2 2.2kQ Kirchhoff's Voltage Law KVL Loop 1 (Nodes a b e fa): KVL Loop 2 (Nodes b c d e b): Kirchhoff's Current Law KCL: i, = i₂+ iz Ohm's Law V=iR V3 R3 2.2kQ R5 1kQ V5 V4 d R4 1kQ Substitute resistor values into Ohm's Law formulas. Put those values into KVL equations. Example: V₁ = i₁* R₁ V₁ = i₁* 1 V₁ = i₁ Just realize that since the resistors in this circuit are in KQ, then current will be in μA. Using the two KVL equations and the KCL equation, use substitution and you will have 3 equations and 3 unknowns, i, i2, and i3. Solve for all three currents. Then plug the currents into each Ohm's Law equation to solve for all six voltages. Finally, verify the KVL equations by plugging in the voltages. Part 2: Solve for the voltage drops across the 330 resistor or resistor series and place the answers in the table.
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