explain your observation thanks! Circuit connection for minimum current delivered by a 30V DC source: ParallelAssigned resistance values: R1 = 25 Q, R; = 50 N, R; = 75 .Table 6.2RDataRR3Simulated Datai = 1.2 A|V; = 30Vi +i, +i;= 2.2Aiz =600mAV = 30Vi; = 400mAV; = 30Vi= 2.2AV;= 30 VSimulated iSimulated VComputed Data30V30VV30Viz=2.2 AComputed i25R5075= 1.2 A4+ i, + i; = 2.2P:= 30 x 1.2= 0.6 A= 0.4 A%3DComputedPower, PP =P2= 30 x 0.06= 18P; = 30 x= 12P, = 66 W= 36 WP + P; + P; = 66W v 30.000Vv 30.000Vv 30.000V1.2000Ai 600.00mAi 400.00mAR1R2R3V130V250500750v 30.000Vi 3.0000Av 30.000Vi 3.0000Av 30.000Vi 3.0000AR1R2R3V110010010030V

Note: As per Bartleby guidelines, we are supposed to provide solution of first question only , I…

Circuit connection for minimum current delivered by a 30V DC source: Parallel Assigned resistance values: R1 = 25 Q, R; = 50 N, R3 = 75 n Table 6.2 R R3 Data Simulated Data Simulated i Simulated V R i = 1.2 A V;= 30V i +i, +i;= 2.2A i, =600mA V; = 30V i = 400mA V; = 30V i-= 2.2A |V;= 30 V Computed Data 30V %3D R iz=2.2 A 30V 30V iz = Computed i 25 R 50 75 = 1.2 A is + i, + i, = 2.2 P;= 30 x 1. 2 = 36 W = 0.6 A = 0.4 A Computed Power, P P7 = P2= 30 x 0.06 = 18 P3 = 30 x = 12 P; = 66 W %3D P; + P; + P, = 66W

Circuit connection for minimum current delivered by a 30V DC source: Parallel Assigned resistance values: R1 = 25 Q, R; = 50 N, R3 = 75 n Table 6.2 R R3 Data Simulated Data Simulated i Simulated V R i = 1.2 A V;= 30V i +i, +i;= 2.2A i, =600mA V; = 30V i = 400mA V; = 30V i-= 2.2A |V;= 30 V Computed Data 30V %3D R iz=2.2 A 30V 30V iz = Computed i 25 R 50 75 = 1.2 A is + i, + i, = 2.2 P;= 30 x 1. 2 = 36 W = 0.6 A = 0.4 A Computed Power, P P7 = P2= 30 x 0.06 = 18 P3 = 30 x = 12 P; = 66 W %3D P; + P; + P, = 66W

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Wheatstone Bridge Method

A Wheatstone bridge is a circuit used to measure unknown resistance by measuring the ratios of the two branches of the circuit such that each branch has two resistance and out of four resistance one is unknown. The two branches are joined in between with the help of galvanometer which is used to determine the direction of the current. The main advantage of this circuit is that it can provide the most accurate measurement (different from a simple voltage separator).

Question

explain your observation thanks!

Circuit connection for minimum current delivered by a 30V DC source: Parallel
Assigned resistance values: R1 = 25 Q, R; = 50 N, R; = 75 .
Table 6.2
R
Data
R
R3
Simulated Data
i = 1.2 A
|V; = 30V
i +i, +i;= 2.2A
iz =600mA
V = 30V
i; = 400mA
V; = 30V
i= 2.2A
V;= 30 V
Simulated i
Simulated V
Computed Data
30V
30V
V
30V
iz=2.2 A
Computed i
25
R
50
75
= 1.2 A
4+ i, + i; = 2.2
P:= 30 x 1.2
= 0.6 A
= 0.4 A
%3D
Computed
Power, P
P =
P2= 30 x 0.06
= 18
P; = 30 x
= 12
P, = 66 W
= 36 W
P + P; + P; = 66W

v 30.000V
v 30.000V
v 30.000V
1.2000A
i 600.00mA
i 400.00mA
R1
R2
R3
V1
30V
250
500
750
v 30.000V
i 3.0000A
v 30.000V
i 3.0000A
v 30.000V
i 3.0000A
R1
R2
R3
V1
100
100
100
30V

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