-cientists tested each in a sample of 4 alleles of antigen-produced protein for level of peptide. The results were x= 1,49 and s=0.15, Use this information to construct a 99% confidence interval for the true variation in peptide scores for alleles of ne antigen-produced protein. Interpret the interval for the scientists. The 99% confidence interval is (OD Round to four decimal places as needed.) nterpret the interval, Select the correct choice below and fill in the answer box(es) to complete your choice. Round to four decimal places as needed.) O A. With 99% confidence, researchers can say that the population variance is between and. O B. With 1% confidence, researchers can say that the population variance is between and. O C. With 99% confidence, researchers can say that the population variance is greater than. O D. With 1% confidence, researchers can say that the population variance is less than

-cientists tested each in a sample of 4 alleles of antigen-produced protein for level of peptide. The results were x= 1,49 and s=0.15, Use this information to construct a 99% confidence interval for the true variation in peptide scores for alleles of ne antigen-produced protein. Interpret the interval for the scientists. The 99% confidence interval is (OD Round to four decimal places as needed.) nterpret the interval, Select the correct choice below and fill in the answer box(es) to complete your choice. Round to four decimal places as needed.) O A. With 99% confidence, researchers can say that the population variance is between and. O B. With 1% confidence, researchers can say that the population variance is between and. O C. With 99% confidence, researchers can say that the population variance is greater than. O D. With 1% confidence, researchers can say that the population variance is less than

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Alessandro constructed three confidence intervals, all from the same random sample. The confidence levels are 90%, 95%, and 99%. The confidence intervals are Ⅰ. <6.2<μ7.8 Ⅱ. <6.1<μ7.9 Ⅲ. <5.8<μ8.2 Unfortunately, Alessandro has forgotten which confidence interval has which level. Match each confidence interval with its level.
Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean ALT levels for the individuals who do not drink alcohol is 32 with a standard deviation of 14, and 37 individuals were in the sample. The mean ALT levels for individuals who drink alcohol is 69 with a standard deviation of 19, and 38 individuals were in the sample. Construct and interpret a 95% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol.
A random sample of 500 males included 215 that approved of the performance of a President. A random sample of 500 females included 185 that approved of the performance of a President. Determine each of the following parts that will lead you to construct a 95% confidence interval for the overall difference in the percentage of males and females that approve of the President's performance. group one males, gorup 2 females Calculate E, the margin of error, for a 95% level of confidence, Create the final confidence interval for the difference in percentages
Alfredo wants a 85% confidence interval for the true average gas mileage for a Gremlin after randomly sampling 9 Gremlins. It is known that the true sigma for Gremlin gas mileage is 4 mpg, and the average of the 9 Gremlins in Alfredo's study was 24 mpg. Find the confidence interval assuming the distribution is normal.
A statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years. The mean score over all those students on the first midterm was u = 88 with standard deviation o = 10. One year, the teacher taught a %3D much smaller class of only 25 students. The teacher wanted to know if teaching a smaller class was more effective and students performed better. We can consider the small class as an SRS of the students who took the large class over the years. The average midterm score was = 78. The hypothesis should be: a. Ho: H = 78 vs. Ha: H = 88. %3D O b. Ho: µ = 88 vs. Ha: µ 78 %3D Ο d. Ho: μ-88 νs. Ha: μ >88. %3D
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One scientist wondered if there was a difference in the average daily intake of dairy products between men and women. He took a sample of n1 = 50 adult men and n2 = 50 adult women and recorded their daily intake of dairy products in grams per day. A summary of the sample results is presented in the table. Construct a 95% confidence interval for the difference in the average daily intake of dairy products for men and women. Can it be concluded that there is a difference in the average daily intakes for men and women?
A researcher was interested in comparing weekly salaries between men and women. Independent samples were drawn to find the average salary for each group. A 90% confidence interval for the difference between female and male employees was determined to be (-$110, $10) in a given week. Interpret the confidence interval Zero is contained in the interval so the probability that male employees earn the same as females is 0.9. 90% of the time, women earn less than men. ore per ek Based on these data, we would assume that female employees average between $110 and $10 than male employees O We are 90% confident that men earn between $110 less or $10 more than women in a given week.
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Find a 99% confidence interval on the difference in the mean life. Car Brand 1 Brand 2 1 36,925 34,318 2 45,300 42,280 3 36,256 35.548 4 32,100 31,950 5 37,210 38,015 6 48,360 47,800 7 38.200 37,810 8 33,500 33,215 Round your answer to 2 decimal places. Do not use commas.
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A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
The confidence level is 99% , o= 4178 thousand dollars, and the histogram of 59 player salaries of football players. Find the critical value za/2 and ta/2